| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2013 |
| Session | June |
| Marks | 10 |
| Paper | Download PDF ↗ |
| Topic | Projectiles |
| Type | Horizontal projection from height |
| Difficulty | Moderate -0.8 This is a straightforward horizontal projectile question requiring only standard SUVAT equations applied separately to vertical and horizontal motion. Part (a) uses s=ut+½at² with u=0, part (b) uses horizontal distance/time, and part (c) combines horizontal and vertical components using Pythagoras. All steps are routine applications of memorized formulas with no problem-solving insight required. |
| Spec | 3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model |
6 In a scene from an action movie, a car is driven off the edge of a cliff and lands on the deck of a boat in the sea, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{cb5001b1-1744-439f-aa35-8dd01bc90421-4_355_1406_427_324}
To land on the boat, the car must move 20 metres horizontally from the cliff. The level of the deck of the boat is 8 metres below the top of the cliff. Assume that the car is a particle which is travelling horizontally when it leaves the top of the cliff and that the car is not affected by air resistance as it moves.
\begin{enumerate}[label=(\alph*)]
\item Find the time that it takes for the car to reach the deck of the boat.
\item Find the speed at which the car is travelling when it leaves the top of the cliff.
\item Find the speed of the car when it hits the deck of the boat.
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2013 Q6 [10]}}