AQA M1 2005 June — Question 1 7 marks

Exam BoardAQA
ModuleM1 (Mechanics 1)
Year2005
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCollision with vector velocities
DifficultyModerate -0.3 This is a straightforward application of conservation of momentum in two dimensions with coalescence. Part (a) requires setting up momentum conservation in the i-direction to find m (simple algebra), and part (b) uses the j-direction to find V. Both parts are direct substitution into the standard formula with no conceptual challenges or problem-solving required beyond routine mechanics.
Spec1.02c Simultaneous equations: two variables by elimination and substitution6.03b Conservation of momentum: 1D two particles

1 A particle of mass \(m\) has velocity \(\left[ \begin{array} { l } 4 \\ 2 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }\). It then collides with a particle of mass 3 kg which has velocity \(\left[ \begin{array} { l } - 1 \\ - 1 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }\). During the collision the particles coalesce and move with velocity \(\left[ \begin{array} { l } 1 \\ V \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }\).
  1. Show that \(m = 2\).
  2. Find \(V\).

Question 1:
Part (a)
AnswerMarks Guidance
WorkingMarks Guidance
\(m\begin{bmatrix}4\\2\end{bmatrix}+3\begin{bmatrix}-1\\-1\end{bmatrix}=(m+3)\begin{bmatrix}1\\V\end{bmatrix}\)M1 Conservation of momentum equation with 3 terms
\(4m-3=m+3\)A1 Correct momentum equation
\(3m=6\)M1 Solving equation
\(m=2\)A1 Correct \(m\) from correct working; deduct one mark for using \(mg\) instead of \(m\)
Part (b)
AnswerMarks Guidance
WorkingMarks Guidance
\(4-3=5V\)M1 Conservation of momentum equation for component containing \(V\)
A1Correct equation
\(V=0.2\)A1 Correct \(V\)
## Question 1:

**Part (a)**

| Working | Marks | Guidance |
|---------|-------|----------|
| $m\begin{bmatrix}4\\2\end{bmatrix}+3\begin{bmatrix}-1\\-1\end{bmatrix}=(m+3)\begin{bmatrix}1\\V\end{bmatrix}$ | M1 | Conservation of momentum equation with 3 terms |
| $4m-3=m+3$ | A1 | Correct momentum equation |
| $3m=6$ | M1 | Solving equation |
| $m=2$ | A1 | Correct $m$ from correct working; deduct one mark for using $mg$ instead of $m$ |

**Part (b)**

| Working | Marks | Guidance |
|---------|-------|----------|
| $4-3=5V$ | M1 | Conservation of momentum equation for component containing $V$ |
| | A1 | Correct equation |
| $V=0.2$ | A1 | Correct $V$ |

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1 A particle of mass $m$ has velocity $\left[ \begin{array} { l } 4 \\ 2 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }$. It then collides with a particle of mass 3 kg which has velocity $\left[ \begin{array} { l } - 1 \\ - 1 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }$. During the collision the particles coalesce and move with velocity $\left[ \begin{array} { l } 1 \\ V \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Show that $m = 2$.
\item Find $V$.
\end{enumerate}

\hfill \mbox{\textit{AQA M1 2005 Q1 [7]}}