AQA S1 2007 June — Question 6 13 marks

Exam BoardAQA
ModuleS1 (Statistics 1)
Year2007
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeProbability of range of values
DifficultyStandard +0.3 This is a straightforward binomial distribution question requiring standard calculations: P(X ≤ 3) and P(10 < X < 20) using tables, finding mean/SD using np and √(np(1-p)), calculating sample statistics, and a basic comparison comment. All techniques are routine S1 content with no novel problem-solving required, making it slightly easier than average.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities2.04d Normal approximation to binomial

6 Each weekday, Monday to Friday, Trina catches a train from her local station. She claims that the probability that the train arrives on time at the station is 0.4 , and that the train's arrival time is independent from day to day.
  1. Assuming her claims to be true, determine the probability that the train arrives on time at the station:
    1. on at most 3 days during a 2 -week period ( 10 days);
    2. on more than 10 days but fewer than 20 days during an 8-week period.
    1. Assuming Trina's claims to be true, determine the mean and standard deviation for the number of times during a week (5 days) that the train arrives on time at the station.
    2. Each week, for a period of 13 weeks, Trina's travelling colleague, Suzie, records the number of times that the train arrives on time at the station. Suzie's results are
      2241233220320
      Calculate the mean and standard deviation of these values.
    3. Hence comment on the likely validity of Trina's claims.

Question 6:
Part (a)
AnswerMarks Guidance
AnswerMark Guidance
Use of binomial in (a) or (b)(i)M1 PI
Part (a)(i)
AnswerMarks Guidance
AnswerMark Guidance
\(P(T_{10} \leq 3) = 0.38\) to \(0.383\)B1 AWFW; \((0.3823)\)
Part (a)(ii)
AnswerMarks Guidance
AnswerMark Guidance
\(P(10 < T_{40} < 20) = 0.8702\) or \(0.9256\)M1 Allow 3 dp accuracy
minus \(0.0352\) or \(0.0156\)M1 Allow 3 dp accuracy
\(= 0.83\) to \(0.84\)A1 AWFW; \((0.835)\)
OR \(B(40, 0.40)\) expressions stated for at least 3 terms within \(10 \leq T_{40} \leq 20\)(M1) Or implied by a correct answer
Answer \(= 0.83\) to \(0.84\)(A2) AWFW
Part (b)(i)
AnswerMarks Guidance
AnswerMark Guidance
\(n = 5\), \(p = 0.4\)
Mean, \(\mu = np = 2\)B1 CAO
Variance, \(\sigma^2 = np(1-p) = 1.2\)M1 Use of \(np(1-p)\) even if SD
Standard deviation \(= \sqrt{1.2} = 1.09\) to \(1.1\)A1 CAO; AWFW
Part (b)(ii)
AnswerMarks Guidance
AnswerMark Guidance
Mean \((\bar{x}) = 2\)B1 CAO; \(\sum x = 26\)
Standard Deviation \((s_n, s_{n-1}) = 1.1\) to \(1.16\)B2 AWFW; \(\sum x^2 = 68\); \((1.1094\) or \(1.1547)\)
If neither correct but use of mean \((\bar{x}) = \frac{\sum x}{13}\)(M1)
Part (b)(iii)
AnswerMarks Guidance
AnswerMark Guidance
Means are same and SDs are similar/same or Means are same but SDs are differentB1 Must have scored full marks in (b)(i) and (b)(ii)
so Trina's claims appear valid/invalid↑Dep↑ B1
# Question 6:

## Part (a)
| Answer | Mark | Guidance |
|--------|------|----------|
| Use of binomial in (a) or (b)(i) | M1 | PI |

## Part (a)(i)
| Answer | Mark | Guidance |
|--------|------|----------|
| $P(T_{10} \leq 3) = 0.38$ to $0.383$ | B1 | AWFW; $(0.3823)$ |

## Part (a)(ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| $P(10 < T_{40} < 20) = 0.8702$ or $0.9256$ | M1 | Allow 3 dp accuracy |
| minus $0.0352$ or $0.0156$ | M1 | Allow 3 dp accuracy |
| $= 0.83$ to $0.84$ | A1 | AWFW; $(0.835)$ |
| **OR** $B(40, 0.40)$ expressions stated for at least 3 terms within $10 \leq T_{40} \leq 20$ | (M1) | Or implied by a correct answer |
| Answer $= 0.83$ to $0.84$ | (A2) | AWFW |

## Part (b)(i)
| Answer | Mark | Guidance |
|--------|------|----------|
| $n = 5$, $p = 0.4$ | — | — |
| Mean, $\mu = np = 2$ | B1 | CAO |
| Variance, $\sigma^2 = np(1-p) = 1.2$ | M1 | Use of $np(1-p)$ even if SD |
| Standard deviation $= \sqrt{1.2} = 1.09$ to $1.1$ | A1 | CAO; AWFW |

## Part (b)(ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| Mean $(\bar{x}) = 2$ | B1 | CAO; $\sum x = 26$ |
| Standard Deviation $(s_n, s_{n-1}) = 1.1$ to $1.16$ | B2 | AWFW; $\sum x^2 = 68$; $(1.1094$ or $1.1547)$ |
| If neither correct but use of mean $(\bar{x}) = \frac{\sum x}{13}$ | (M1) | — |

## Part (b)(iii)
| Answer | Mark | Guidance |
|--------|------|----------|
| Means are same and SDs are similar/same **or** Means are same but SDs are different | B1 | Must have scored full marks in (b)(i) and (b)(ii) |
| so Trina's claims appear valid/invalid | ↑Dep↑ B1 | — |

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6 Each weekday, Monday to Friday, Trina catches a train from her local station. She claims that the probability that the train arrives on time at the station is 0.4 , and that the train's arrival time is independent from day to day.
\begin{enumerate}[label=(\alph*)]
\item Assuming her claims to be true, determine the probability that the train arrives on time at the station:
\begin{enumerate}[label=(\roman*)]
\item on at most 3 days during a 2 -week period ( 10 days);
\item on more than 10 days but fewer than 20 days during an 8-week period.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Assuming Trina's claims to be true, determine the mean and standard deviation for the number of times during a week (5 days) that the train arrives on time at the station.
\item Each week, for a period of 13 weeks, Trina's travelling colleague, Suzie, records the number of times that the train arrives on time at the station. Suzie's results are

\begin{center}
\begin{tabular}{ l l l l l l l l l l l l l }
2 & 2 & 4 & 1 & 2 & 3 & 3 & 2 & 2 & 0 & 3 & 2 & 0 \\
\end{tabular}
\end{center}

Calculate the mean and standard deviation of these values.
\item Hence comment on the likely validity of Trina's claims.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA S1 2007 Q6 [13]}}