Edexcel C4 — Question 4 6 marks

Exam BoardEdexcel
ModuleC4 (Core Mathematics 4)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeTrapezium rule applied to real-world data
DifficultyModerate -0.3 This is a straightforward application of the trapezium rule with a minor twist of squaring values first. Students must calculate V², apply the standard trapezium rule formula with h=0.25, then take a square root. It's slightly easier than average because it's purely procedural with clear instructions and no conceptual challenges beyond basic formula application.
Spec1.09f Trapezium rule: numerical integration

  1. A measure of the effective voltage, \(M\) volts, in an electrical circuit is given by
$$M ^ { 2 } = \int _ { 0 } ^ { 1 } V ^ { 2 } \mathrm {~d} t$$ where \(V\) volts is the voltage at time \(t\) seconds. Pairs of values of \(V\) and \(t\) are given in the following table.
\(t\)00.250.50.751
\(V\)- 4820737- 161- 29
\(V ^ { 2 }\)
Use the trapezium rule with five values of \(V ^ { 2 }\) to estimate the value of \(M\).
(6)

Question 4:
AnswerMarks Guidance
\(V^2\) values: \((-48)^2=2304\), \(207^2=42849\), \(37^2=1369\), \((-161)^2=25921\), \((-29)^2=841\)B1 At least 4 correct \(V^2\) values
Trapezium rule: \(M^2 \approx \frac{1}{2}(0.25)[(2304+841)+2(42849+1369+25921)]\)M1 Correct application with \(h=0.25\)
\(= \frac{0.25}{2}[3145 + 2(70139)]\)
\(= \frac{0.25}{2}[143423]\)
\(M^2 \approx 17927.875\)A1 Correct value
\(M \approx 133.9\)A1 \(M\) found by square root
# Question 4:
| $V^2$ values: $(-48)^2=2304$, $207^2=42849$, $37^2=1369$, $(-161)^2=25921$, $(-29)^2=841$ | B1 | At least 4 correct $V^2$ values |
| Trapezium rule: $M^2 \approx \frac{1}{2}(0.25)[(2304+841)+2(42849+1369+25921)]$ | M1 | Correct application with $h=0.25$ |
| $= \frac{0.25}{2}[3145 + 2(70139)]$ | | |
| $= \frac{0.25}{2}[143423]$ | | |
| $M^2 \approx 17927.875$ | A1 | Correct value |
| $M \approx 133.9$ | A1 | $M$ found by square root |

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\begin{enumerate}
  \item A measure of the effective voltage, $M$ volts, in an electrical circuit is given by
\end{enumerate}

$$M ^ { 2 } = \int _ { 0 } ^ { 1 } V ^ { 2 } \mathrm {~d} t$$

where $V$ volts is the voltage at time $t$ seconds. Pairs of values of $V$ and $t$ are given in the following table.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
$t$ & 0 & 0.25 & 0.5 & 0.75 & 1 \\
\hline
$V$ & - 48 & 207 & 37 & - 161 & - 29 \\
\hline
$V ^ { 2 }$ &  &  &  &  &  \\
\hline
\end{tabular}
\end{center}

Use the trapezium rule with five values of $V ^ { 2 }$ to estimate the value of $M$.\\
(6)\\

\hfill \mbox{\textit{Edexcel C4  Q4 [6]}}