AQA C4 2011 June — Question 1 7 marks

Exam BoardAQA
ModuleC4 (Core Mathematics 4)
Year2011
SessionJune
Marks7
PaperDownload PDF ↗
TopicFactor & Remainder Theorem
TypeVerify factor then simplify rational expression
DifficultyModerate -0.8 This is a straightforward application of the Factor Theorem with routine algebraic manipulation. Part (a) is direct substitution, part (b) requires evaluating f(3/2) to verify the factor, and part (c) involves factoring both numerator and denominator then canceling common factors. All steps are standard textbook exercises requiring no problem-solving insight, making it easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02k Simplify rational expressions: factorising, cancelling, algebraic division

1 The polynomial \(\mathrm { f } ( x )\) is defined by \(\mathrm { f } ( x ) = 4 x ^ { 3 } - 13 x + 6\).
  1. Find \(\mathrm { f } ( - 2 )\).
  2. Use the Factor Theorem to show that \(2 x - 3\) is a factor of \(\mathrm { f } ( x )\).
  3. Simplify \(\frac { 2 x ^ { 2 } + x - 6 } { \mathrm { f } ( x ) }\).

1 The polynomial $\mathrm { f } ( x )$ is defined by $\mathrm { f } ( x ) = 4 x ^ { 3 } - 13 x + 6$.
\begin{enumerate}[label=(\alph*)]
\item Find $\mathrm { f } ( - 2 )$.
\item Use the Factor Theorem to show that $2 x - 3$ is a factor of $\mathrm { f } ( x )$.
\item Simplify $\frac { 2 x ^ { 2 } + x - 6 } { \mathrm { f } ( x ) }$.
\end{enumerate}

\hfill \mbox{\textit{AQA C4 2011 Q1 [7]}}