AQA C3 2008 January — Question 7 12 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2008
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch y=|f(x)| or y=f(|x|) for non-linear f(x) and solve
DifficultyStandard +0.3 This is a straightforward modulus question requiring standard techniques: identifying transformations (stretch and translation), sketching a modulus graph by reflecting negative parts, and solving |quadratic| = constant by considering two cases. All steps are routine C3 material with no novel problem-solving required, making it slightly easier than average.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02s Modulus graphs: sketch graph of |ax+b|1.02t Solve modulus equations: graphically with modulus function1.02w Graph transformations: simple transformations of f(x)

7
  1. Describe a sequence of two geometrical transformations that maps the graph of \(y = x ^ { 2 }\) onto the graph of \(y = 4 x ^ { 2 } - 5\).
  2. Sketch the graph of \(y = \left| 4 x ^ { 2 } - 5 \right|\), indicating the coordinates of the point where the curve crosses the \(y\)-axis.
    1. Solve the equation \(\left| 4 x ^ { 2 } - 5 \right| = 4\).
    2. Hence, or otherwise, solve the inequality \(\left| 4 x ^ { 2 } - 5 \right| \geqslant 4\).

7(a)
AnswerMarks Guidance
Stretch (I)M1 \(1 + \) (II or III)
Scale factor \(\frac{1}{2}\) (II)A1 All correct
parallel to \(x\)-axis (III)
(Or scale factor 4 parallel to \(y\)-axis)
TranslationM1
\(\begin{pmatrix}0\\-5\end{pmatrix}\) OEA1
Alternatives:
AnswerMarks Guidance
translate \(\begin{pmatrix}0\\-5\\-4\end{pmatrix}\), stretch of 4 ∥ \(y\)-axis Mark translation first. Mark stretch as above, but relative to their translation.
translate \(\begin{pmatrix}0\\-5\end{pmatrix}\), stretch sf \(\frac{1}{2}\) ∥ \(x\)-axis
7(b)
AnswerMarks Guidance
[Graph showing modulus function with V-shape, vertex at (0,5)]M1 Modulus graph symmetrical about \(y\)-axis
A1left of \(-\frac{\sqrt{5}}{2}\) and right of \(\frac{\sqrt{5}}{2}\)
A1\((0, 5)\), cusps drawn and no straight lines between cusps Total: 3
7(c)(i)
AnswerMarks Guidance
\(4x^2 - 5 = 4\)B1 OE
\(4x^2 = 9\)
\(x = \pm\frac{3}{2}\)
\(4x^2 - 5 = -4\)M1 \(16x^4 - 40x^2 + 9 = 0\)
\(4x^2 = 1\)
\(x = \pm\frac{1}{2}\)A1
7(c)(ii)
AnswerMarks Guidance
\(x \leq -\frac{3}{2}, x \geq \frac{3}{2}\)B1 F 2 correct statements
\(-\frac{1}{2} \leq x, x \leq \frac{1}{2}\)B1 F 4 correct statements
SC c(ii): 1 mark penalty for strict inequalities
### 7(a)
Stretch (I) | M1 | $1 + $ (II or III) |

Scale factor $\frac{1}{2}$ (II) | A1 | All correct |

parallel to $x$-axis (III) | | |

(Or scale factor 4 parallel to $y$-axis) | | |

Translation | M1 | |

$\begin{pmatrix}0\\-5\end{pmatrix}$ OE | A1 | | **Total: 4**

**Alternatives:**

translate $\begin{pmatrix}0\\-5\\-4\end{pmatrix}$, stretch of 4 ∥ $y$-axis | | Mark translation first. Mark stretch as above, but relative to their translation. |

translate $\begin{pmatrix}0\\-5\end{pmatrix}$, stretch sf $\frac{1}{2}$ ∥ $x$-axis | | |

### 7(b)
[Graph showing modulus function with V-shape, vertex at (0,5)] | M1 | Modulus graph symmetrical about $y$-axis |

| A1 | left of $-\frac{\sqrt{5}}{2}$ and right of $\frac{\sqrt{5}}{2}$ |

| A1 | $(0, 5)$, cusps drawn and no straight lines between cusps | **Total: 3**

### 7(c)(i)
$4x^2 - 5 = 4$ | B1 | OE |

$4x^2 = 9$ | | |

$x = \pm\frac{3}{2}$ | | |

$4x^2 - 5 = -4$ | M1 | $16x^4 - 40x^2 + 9 = 0$ |

$4x^2 = 1$ | | |

$x = \pm\frac{1}{2}$ | A1 | | **Total: 3**

### 7(c)(ii)
$x \leq -\frac{3}{2}, x \geq \frac{3}{2}$ | B1 F | 2 correct statements |

$-\frac{1}{2} \leq x, x \leq \frac{1}{2}$ | B1 F | 4 correct statements | **Total: 2**

| | | **SC c(ii):** 1 mark penalty for strict inequalities |
7
\begin{enumerate}[label=(\alph*)]
\item Describe a sequence of two geometrical transformations that maps the graph of $y = x ^ { 2 }$ onto the graph of $y = 4 x ^ { 2 } - 5$.
\item Sketch the graph of $y = \left| 4 x ^ { 2 } - 5 \right|$, indicating the coordinates of the point where the curve crosses the $y$-axis.
\item \begin{enumerate}[label=(\roman*)]
\item Solve the equation $\left| 4 x ^ { 2 } - 5 \right| = 4$.
\item Hence, or otherwise, solve the inequality $\left| 4 x ^ { 2 } - 5 \right| \geqslant 4$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA C3 2008 Q7 [12]}}