AQA C2 2014 June — Question 5 6 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2014
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeSimultaneous equations with arc/area
DifficultyStandard +0.3 This is a straightforward application of standard arc length and sector area formulas to form two simultaneous equations in r and θ. The setup requires recognizing that perimeter = 2r + rθ = 4(rθ), which gives θ = 2, then substituting into the area formula ½r²θ = 12 to find r. While it involves multiple steps, each is routine and the problem-solving required is minimal—slightly easier than average for A-level.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

5 The diagram shows a sector \(O A B\) of a circle with centre \(O\) and radius \(r \mathrm {~cm}\). \includegraphics[max width=\textwidth, alt={}, center]{30ccdbe9-0c91-4011-a3f9-3ce01862215d-10_346_360_360_824} The angle \(A O B\) is \(\theta\) radians.
The area of the sector is \(12 \mathrm {~cm} ^ { 2 }\).
The perimeter of the sector is four times the length of the \(\operatorname { arc } A B\).
Find the value of \(r\).
[0pt] [6 marks]
\includegraphics[max width=\textwidth, alt={}]{30ccdbe9-0c91-4011-a3f9-3ce01862215d-10_1533_1712_1174_150}

Question 5:
AnswerMarks Guidance
Arc length \(AB = r\theta\)B1 Correct formula stated or used
Perimeter \(= 2r + r\theta\)M1 Correct expression for perimeter
\(2r + r\theta = 4r\theta\)M1 Setting perimeter \(= 4 \times\) arc
\(2r = 3r\theta \Rightarrow \theta = \frac{2}{3}\)A1 Correct value of \(\theta\)
Area \(= \frac{1}{2}r^2\theta = 12\)M1 Using area formula with their \(\theta\)
\(\frac{1}{2}r^2 \times \frac{2}{3} = 12 \Rightarrow r^2 = 36 \Rightarrow r = 6\)A1 \(r = 6\)
## Question 5:

| Arc length $AB = r\theta$ | B1 | Correct formula stated or used |
| Perimeter $= 2r + r\theta$ | M1 | Correct expression for perimeter |
| $2r + r\theta = 4r\theta$ | M1 | Setting perimeter $= 4 \times$ arc |
| $2r = 3r\theta \Rightarrow \theta = \frac{2}{3}$ | A1 | Correct value of $\theta$ |
| Area $= \frac{1}{2}r^2\theta = 12$ | M1 | Using area formula with their $\theta$ |
| $\frac{1}{2}r^2 \times \frac{2}{3} = 12 \Rightarrow r^2 = 36 \Rightarrow r = 6$ | A1 | $r = 6$ |
5 The diagram shows a sector $O A B$ of a circle with centre $O$ and radius $r \mathrm {~cm}$.\\
\includegraphics[max width=\textwidth, alt={}, center]{30ccdbe9-0c91-4011-a3f9-3ce01862215d-10_346_360_360_824}

The angle $A O B$ is $\theta$ radians.\\
The area of the sector is $12 \mathrm {~cm} ^ { 2 }$.\\
The perimeter of the sector is four times the length of the $\operatorname { arc } A B$.\\
Find the value of $r$.\\[0pt]
[6 marks]

\begin{center}
\includegraphics[max width=\textwidth, alt={}]{30ccdbe9-0c91-4011-a3f9-3ce01862215d-10_1533_1712_1174_150}
\end{center}

\hfill \mbox{\textit{AQA C2 2014 Q5 [6]}}