| Exam Board | AQA |
|---|---|
| Module | C2 (Core Mathematics 2) |
| Year | 2006 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Sine and Cosine Rules |
| Type | Sequential triangle calculations (basic) |
| Difficulty | Easy -1.2 This is a straightforward two-part question requiring direct application of the sine rule to find an angle, then the standard area formula (½ab sin C). Both are routine procedures with no problem-solving required, making it easier than average for A-level, though not trivial since it requires calculator work and accuracy. |
| Spec | 1.05b Sine and cosine rules: including ambiguous case1.05c Area of triangle: using 1/2 ab sin(C) |
2 The diagram shows a triangle $A B C$.\\
\includegraphics[max width=\textwidth, alt={}, center]{f066f68a-e739-4da3-8ec1-e221461146b0-2_757_558_1409_726}
The lengths of $A C$ and $B C$ are 4.8 cm and 12 cm respectively.\\
The size of the angle $B A C$ is $100 ^ { \circ }$.
\begin{enumerate}[label=(\alph*)]
\item Show that angle $A B C = 23.2 ^ { \circ }$, correct to the nearest $0.1 ^ { \circ }$.
\item Calculate the area of triangle $A B C$, giving your answer in $\mathrm { cm } ^ { 2 }$ to three significant figures.
\end{enumerate}
\hfill \mbox{\textit{AQA C2 2006 Q2 [6]}}