AQA C2 2006 June — Question 1 5 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2006
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeSector perimeter calculation
DifficultyModerate -0.8 This is a straightforward application of standard sector formulas (A = ½r²θ and arc length = rθ) with minimal steps. Part (a) requires simple rearrangement and arithmetic, while part (b) is direct substitution. No problem-solving insight needed, just recall and basic calculation.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

1 The diagram shows a sector of a circle of radius 5 cm and angle \(\theta\) radians. \includegraphics[max width=\textwidth, alt={}, center]{f066f68a-e739-4da3-8ec1-e221461146b0-2_327_358_571_842} The area of the sector is \(8.1 \mathrm {~cm} ^ { 2 }\).
  1. Show that \(\theta = 0.648\).
  2. Find the perimeter of the sector.

1 The diagram shows a sector of a circle of radius 5 cm and angle $\theta$ radians.\\
\includegraphics[max width=\textwidth, alt={}, center]{f066f68a-e739-4da3-8ec1-e221461146b0-2_327_358_571_842}

The area of the sector is $8.1 \mathrm {~cm} ^ { 2 }$.
\begin{enumerate}[label=(\alph*)]
\item Show that $\theta = 0.648$.
\item Find the perimeter of the sector.
\end{enumerate}

\hfill \mbox{\textit{AQA C2 2006 Q1 [5]}}