Edexcel C1 — Question 3 6 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeFind derivative after algebraic simplification (fractional/mixed powers)
DifficultyModerate -0.8 This is a straightforward integration question requiring only the reverse power rule and using a point to find the constant of integration. It's easier than average as it involves basic C1 integration with a simple fractional power and no problem-solving complexity beyond applying standard techniques.
Spec1.07i Differentiate x^n: for rational n and sums1.08a Fundamental theorem of calculus: integration as reverse of differentiation

  1. The curve with equation \(y = \mathrm { f } ( x )\) passes through the point (8, 7).
Given that $$\mathrm { f } ^ { \prime } ( x ) = 4 x ^ { \frac { 1 } { 3 } } - 5$$ find \(\mathrm { f } ( x )\).

Question 3:
AnswerMarks Guidance
Answer/WorkingMarks Notes
\(\text{f}(x) = 3x^{\frac{4}{3}} - 5x + c\)M1 A2
\((8,7)\): \(7 = 3(\sqrt[3]{8})^4 - 40 + c\), i.e. \(7 = 48 - 40 + c\)M1
\(c = -1\)M1
\(\text{f}(x) = 3x^{\frac{4}{3}} - 5x - 1\)A1 (6)
## Question 3:

| Answer/Working | Marks | Notes |
|---|---|---|
| $\text{f}(x) = 3x^{\frac{4}{3}} - 5x + c$ | M1 A2 | |
| $(8,7)$: $7 = 3(\sqrt[3]{8})^4 - 40 + c$, i.e. $7 = 48 - 40 + c$ | M1 | |
| $c = -1$ | M1 | |
| $\text{f}(x) = 3x^{\frac{4}{3}} - 5x - 1$ | A1 | **(6)** |

---
\begin{enumerate}
  \item The curve with equation $y = \mathrm { f } ( x )$ passes through the point (8, 7).
\end{enumerate}

Given that

$$\mathrm { f } ^ { \prime } ( x ) = 4 x ^ { \frac { 1 } { 3 } } - 5$$

find $\mathrm { f } ( x )$.\\

\hfill \mbox{\textit{Edexcel C1  Q3 [6]}}