AQA C1 2014 June — Question 4 7 marks

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2014
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeSketch quadratic curve
DifficultyModerate -0.8 This is a routine C1 completing-the-square question with standard follow-up parts. Part (a) requires mechanical completion of the square, part (b) straightforward factorisation and sketching. All techniques are textbook exercises with no problem-solving or novel insight required, making it easier than average but not trivial due to the multi-step nature.
Spec1.02e Complete the square: quadratic polynomials and turning points1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02n Sketch curves: simple equations including polynomials

4
    1. Express \(16 - 6 x - x ^ { 2 }\) in the form \(p - ( x + q ) ^ { 2 }\) where \(p\) and \(q\) are integers.
    2. Hence write down the maximum value of \(16 - 6 x - x ^ { 2 }\).
    1. Factorise \(16 - 6 x - x ^ { 2 }\).
    2. Sketch the curve with equation \(y = 16 - 6 x - x ^ { 2 }\), stating the values of \(x\) where the curve crosses the \(x\)-axis and the value of the \(y\)-intercept.
      [0pt] [3 marks]

Question 4:
Part (a)(i)
AnswerMarks Guidance
AnswerMark Guidance
\(16 - 6x - x^2 = -(x^2 + 6x - 16)\)M1 Attempt completing the square
\(= 25 - (x+3)^2\)A1 \(p=25\), \(q=3\)
Part (a)(ii)
AnswerMarks Guidance
AnswerMark Guidance
Maximum value \(= 25\)B1 Follow through from (a)(i)
Part (b)(i)
AnswerMarks Guidance
AnswerMark Guidance
\(16 - 6x - x^2 = (2-x)(8+x)\)B1 Accept equivalent forms
Part (b)(ii)
AnswerMarks Guidance
AnswerMark Guidance
Curve crosses \(x\)-axis at \(x=2\) and \(x=-8\)B1
\(y\)-intercept at \((0, 16)\)B1
Correct inverted parabola shape through stated pointsB1
# Question 4:

## Part (a)(i)
| Answer | Mark | Guidance |
|--------|------|----------|
| $16 - 6x - x^2 = -(x^2 + 6x - 16)$ | M1 | Attempt completing the square |
| $= 25 - (x+3)^2$ | A1 | $p=25$, $q=3$ |

## Part (a)(ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| Maximum value $= 25$ | B1 | Follow through from (a)(i) |

## Part (b)(i)
| Answer | Mark | Guidance |
|--------|------|----------|
| $16 - 6x - x^2 = (2-x)(8+x)$ | B1 | Accept equivalent forms |

## Part (b)(ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| Curve crosses $x$-axis at $x=2$ and $x=-8$ | B1 | |
| $y$-intercept at $(0, 16)$ | B1 | |
| Correct inverted parabola shape through stated points | B1 | |

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4
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Express $16 - 6 x - x ^ { 2 }$ in the form $p - ( x + q ) ^ { 2 }$ where $p$ and $q$ are integers.
\item Hence write down the maximum value of $16 - 6 x - x ^ { 2 }$.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Factorise $16 - 6 x - x ^ { 2 }$.
\item Sketch the curve with equation $y = 16 - 6 x - x ^ { 2 }$, stating the values of $x$ where the curve crosses the $x$-axis and the value of the $y$-intercept.\\[0pt]
[3 marks]
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA C1 2014 Q4 [7]}}