AQA C1 2005 June — Question 7 7 marks

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2005
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeSolve quadratic inequality
DifficultyEasy -1.2 This is a straightforward C1 question testing basic inequality manipulation and factorising a simple quadratic. Part (a) requires only linear algebra (expanding brackets, collecting terms), and part (b) is a standard quadratic inequality requiring factorisation of x²-x-6 into (x-3)(x+2) and identifying the negative region. Both are routine textbook exercises with no problem-solving insight required, making this easier than average.
Spec1.02g Inequalities: linear and quadratic in single variable

7 Solve each of the following inequalities:
  1. \(3 ( x - 1 ) > 3 - 5 ( x + 6 )\);
  2. \(\quad x ^ { 2 } - x - 6 < 0\).

Question 7:
Part (a)
AnswerMarks Guidance
WorkingMarks Guidance
\(3x - 3 > 3 - 5x - 30\)M1 Multiplying out (condone one slip)
\(\Rightarrow 8x > -24\)A1 Or correct equivalent e.g. \(-8x < 24\)
\(\Rightarrow x > -3\)A1 (Penalise \(\leqslant\), \(\geqslant\) once only in (a) and (b))
Part (b)
AnswerMarks Guidance
WorkingMarks Guidance
\(x^2 - x - 6 = (x-3)(x+2)\)M1 Attempt to use quad formula or factorise
(critical points are) \(3\) and \(-2\)A1 May be seen in diagram or solution
Sketch or sign diagramM1
\(2 < x < 3\)A1
Total: 7 marks
## Question 7:

**Part (a)**
| Working | Marks | Guidance |
|---------|-------|----------|
| $3x - 3 > 3 - 5x - 30$ | M1 | Multiplying out (condone one slip) |
| $\Rightarrow 8x > -24$ | A1 | Or correct equivalent e.g. $-8x < 24$ |
| $\Rightarrow x > -3$ | A1 | (Penalise $\leqslant$, $\geqslant$ once only in (a) and (b)) |

**Part (b)**
| Working | Marks | Guidance |
|---------|-------|----------|
| $x^2 - x - 6 = (x-3)(x+2)$ | M1 | Attempt to use quad formula or factorise |
| (critical points are) $3$ and $-2$ | A1 | May be seen in diagram or solution |
| Sketch or sign diagram | M1 | |
| $2 < x < 3$ | A1 | |

**Total: 7 marks**

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7 Solve each of the following inequalities:
\begin{enumerate}[label=(\alph*)]
\item $3 ( x - 1 ) > 3 - 5 ( x + 6 )$;
\item $\quad x ^ { 2 } - x - 6 < 0$.
\end{enumerate}

\hfill \mbox{\textit{AQA C1 2005 Q7 [7]}}