AQA C1 2006 January — Question 6

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2006
SessionJanuary
TopicFactor & Remainder Theorem
TypeVerify factor then sketch or analyse curve

6 The polynomial \(\mathrm { p } ( x )\) is given by $$\mathrm { p } ( x ) = x ^ { 3 } + x ^ { 2 } - 10 x + 8$$
    1. Using the factor theorem, show that \(x - 2\) is a factor of \(\mathrm { p } ( x )\).
    2. Hence express \(\mathrm { p } ( x )\) as the product of three linear factors.
  1. Sketch the curve with equation \(y = x ^ { 3 } + x ^ { 2 } - 10 x + 8\), showing the coordinates of the points where the curve cuts the axes.
    (You are not required to calculate the coordinates of the stationary points.)