| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(x = \frac{2}{5}\) | B1 | Vertical asymptote. |
| \(y = \dfrac{(5x-2)(x+\frac{2}{5})+\frac{4}{5}}{5x-2}\) leading to \(y = x + \frac{2}{5}\) | M1 A1 | Oblique asymptote. |
| Total: 3 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(\dfrac{dy}{dx} = \dfrac{(5x-2)(10x) - (5x^2)(5)}{(5x-2)^2}\) | M1 | Finds \(\dfrac{dy}{dx}\) |
| \(5x^2 - 4x = 0\) | M1 | Sets equal to 0 and forms quadratic equation. |
| \((0,0)\), \(\left(\frac{4}{5}, \frac{8}{5}\right)\) | A1 A1 | |
| Total: 4 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Axes and asymptotes shown | B1 | Axes and asymptotes. |
| Correct upper branch with asymptotic behaviour | B1 | Correct upper branch and asymptotic behaviour. |
| Correct lower branch | B1 | Correct lower branch. |
| Total: 3 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Sketch of \(\left | \dfrac{5x^2}{5x-2}\right | \) |
| Correct shape as \(x\) tends to infinity | B1 | Correct shape as \(x\) tends to infinity. |
| \(\dfrac{5x^2}{5x-2} = 2\) or \(\dfrac{5x^2}{5x-2} = -2\); \(5x^2 - 10x + 4 = 0\) or \(5x^2 + 10x - 4 = 0\) | M2 | Finds critical points, award M1 for each case. |
| \(x = -1-\frac{3}{5}\sqrt{5}\), \(x = -1+\frac{3}{5}\sqrt{5}\) or \(x = 1-\frac{1}{5}\sqrt{5}\), \(x = 1+\frac{1}{5}\sqrt{5}\) | A1 | Must be exact. |
| \(-1-\frac{3}{5}\sqrt{5} < x < -1+\frac{3}{5}\sqrt{5}\), \(1-\frac{1}{5}\sqrt{5} < x < 1+\frac{1}{5}\sqrt{5}\) | A1 FT | Follow through on use of decimals. |
| Total: 6 |
## Question 7(a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $x = \frac{2}{5}$ | B1 | Vertical asymptote. |
| $y = \dfrac{(5x-2)(x+\frac{2}{5})+\frac{4}{5}}{5x-2}$ leading to $y = x + \frac{2}{5}$ | M1 A1 | Oblique asymptote. |
| **Total: 3** | | |
## Question 7(b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\dfrac{dy}{dx} = \dfrac{(5x-2)(10x) - (5x^2)(5)}{(5x-2)^2}$ | M1 | Finds $\dfrac{dy}{dx}$ |
| $5x^2 - 4x = 0$ | M1 | Sets equal to 0 and forms quadratic equation. |
| $(0,0)$, $\left(\frac{4}{5}, \frac{8}{5}\right)$ | A1 A1 | |
| **Total: 4** | | |
## Question 7(c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Axes and asymptotes shown | B1 | Axes and asymptotes. |
| Correct upper branch with asymptotic behaviour | B1 | Correct upper branch and asymptotic behaviour. |
| Correct lower branch | B1 | Correct lower branch. |
| **Total: 3** | | |
## Question 7(d):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Sketch of $\left|\dfrac{5x^2}{5x-2}\right|$ | B1 FT | FT from sketch in part (c). |
| Correct shape as $x$ tends to infinity | B1 | Correct shape as $x$ tends to infinity. |
| $\dfrac{5x^2}{5x-2} = 2$ or $\dfrac{5x^2}{5x-2} = -2$; $5x^2 - 10x + 4 = 0$ or $5x^2 + 10x - 4 = 0$ | M2 | Finds critical points, award M1 for each case. |
| $x = -1-\frac{3}{5}\sqrt{5}$, $x = -1+\frac{3}{5}\sqrt{5}$ or $x = 1-\frac{1}{5}\sqrt{5}$, $x = 1+\frac{1}{5}\sqrt{5}$ | A1 | Must be exact. |
| $-1-\frac{3}{5}\sqrt{5} < x < -1+\frac{3}{5}\sqrt{5}$, $1-\frac{1}{5}\sqrt{5} < x < 1+\frac{1}{5}\sqrt{5}$ | A1 FT | Follow through on use of decimals. |
| **Total: 6** | | |
7 The curve $C$ has equation $y = \frac { 5 x ^ { 2 } } { 5 x - 2 }$.
\begin{enumerate}[label=(\alph*)]
\item Find the equations of the asymptotes of $C$.
\item Find the coordinates of the stationary points on $C$.
\item Sketch $C$.
\item Sketch the curve with equation $y = \left| \frac { 5 x ^ { 2 } } { 5 x - 2 } \right|$ and find in exact form the set of values of $x$ for which $\left| \frac { 5 x ^ { 2 } } { 5 x - 2 } \right| < 2$.\\
If you use the following page to complete the answer to any question, the question number must be clearly shown.
\end{enumerate}
\hfill \mbox{\textit{CAIE Further Paper 1 2022 Q7 [16]}}