OCR Further Pure Core 1 2019 June — Question 6

Exam BoardOCR
ModuleFurther Pure Core 1 (Further Pure Core 1)
Year2019
SessionJune
TopicIntegration using inverse trig and hyperbolic functions

6 You are given that \(y = \tan ^ { - 1 } \sqrt { 2 x }\).
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\).
  2. Show that \(\int _ { \frac { 1 } { 6 } } ^ { \frac { 1 } { 2 } } \frac { \sqrt { x } } { \left( x + 2 x ^ { 2 } \right) } \mathrm { d } x = k \pi\) where \(k\) is a number to be determined in exact form.