OCR Further Pure Core 1 2019 June — Question 4 3 marks

Exam BoardOCR
ModuleFurther Pure Core 1 (Further Pure Core 1)
Year2019
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeStandard summation formulae application
DifficultyEasy -1.2 This is a straightforward application of standard summation formulae requiring only algebraic manipulation (expanding to 3∑r² - 2∑r) and substitution of n=10 into given formulae. It's a routine Further Maths exercise with no problem-solving or insight required, though slightly above basic A-level due to the Further Pure context.
Spec4.06a Summation formulae: sum of r, r^2, r^3

4 Using the formulae for \(\sum _ { r = 1 } ^ { n } r\) and \(\sum _ { r = 1 } ^ { n } r ^ { 2 }\), show that \(\sum _ { r = 1 } ^ { 10 } r ( 3 r - 2 ) = 1045\).

Question 4:
AnswerMarks
410 10 10 10
∑r(3r−2)=∑(3r2 −2r)=3∑r2 −2∑r
r=1 r=1 r=1 r=1
1  1 
=3 10.11.21 −2 10.11
6  2 
( =55 ( 21−2 )=55×19 )
=1045
Alternative Q3 leaving substitution to the end
10 10 10 10
∑r(3r−2)=∑(3r2 −2r)=3∑r2 −2∑r
M1
r=1 r=1 r=1 r=1
3 2
= n ( n+1 )( 2n+1 )− n ( n+1 )
6 2
1 1
= n ( n+1 )( 2n+1−2 )= n ( n+1 )( 2n−1 )
2 2
1
n=10⇒ 10.11.19 M1
2
AnswerMarks
=1045 A1M1
M1
A1
AnswerMarks
[3]1.1
2.1
AnswerMarks
1.1Separate soi
Use both formulae with n
= 10
AnswerMarks
AGoe 1155 − 110
Question 4:
4 | 10 10 10 10
∑r(3r−2)=∑(3r2 −2r)=3∑r2 −2∑r
r=1 r=1 r=1 r=1
1  1 
=3 10.11.21 −2 10.11
6  2 
( =55 ( 21−2 )=55×19 )
=1045
Alternative Q3 leaving substitution to the end
10 10 10 10
∑r(3r−2)=∑(3r2 −2r)=3∑r2 −2∑r
M1
r=1 r=1 r=1 r=1
3 2
= n ( n+1 )( 2n+1 )− n ( n+1 )
6 2
1 1
= n ( n+1 )( 2n+1−2 )= n ( n+1 )( 2n−1 )
2 2
1
n=10⇒ 10.11.19 M1
2
=1045 A1 | M1
M1
A1
[3] | 1.1
2.1
1.1 | Separate soi
Use both formulae with n
= 10
AG | oe 1155 − 110
4 Using the formulae for $\sum _ { r = 1 } ^ { n } r$ and $\sum _ { r = 1 } ^ { n } r ^ { 2 }$, show that $\sum _ { r = 1 } ^ { 10 } r ( 3 r - 2 ) = 1045$.

\hfill \mbox{\textit{OCR Further Pure Core 1 2019 Q4 [3]}}