OCR Further Mechanics AS 2024 June — Question 1 6 marks

Exam BoardOCR
ModuleFurther Mechanics AS (Further Mechanics AS)
Year2024
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions 1
TypeParticle-wall perpendicular collision
DifficultyModerate -0.8 This is a straightforward application of standard mechanics formulas: coefficient of restitution (e = separation speed / approach speed) and impulse (change in momentum). All three parts require direct substitution into well-known formulas with no problem-solving insight or multi-step reasoning needed. Easier than average A-level mechanics.
Spec6.03e Impulse: by a force6.03i Coefficient of restitution: e6.03j Perfectly elastic/inelastic: collisions

1 A particle \(P\) of mass 2.5 kg is moving with a constant speed of \(4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in a straight line on a smooth horizontal plane when it collides directly with a fixed vertical wall. After the collision \(P\) moves away from the wall with a speed of \(2.8 \mathrm {~ms} ^ { - 1 }\).
  1. Calculate the coefficient of restitution between \(P\) and the wall.
  2. Find the magnitude and state the direction of the impulse exerted on \(P\) by the wall.
  3. State the magnitude and direction of the impulse exerted on the wall by \(P\).

Question 1:
Part (a)
AnswerMarks Guidance
\(e = \frac{0 - (-2.8)}{4 - 0} = 0.7\)B1 [1] oe e.g. \(\frac{2.8}{4} = 0.7\); B0 for \(-0.7\)
Part (b)
AnswerMarks Guidance
Impulse on \(P = \Delta mv = \pm(2.5 \times 4 - 2.5 \times (-2.8))\)M1 Finding change in \(P\)'s momentum; allow 1 slip but not wrong sign inside brackets
\(= 17\) (Ns)A1 Do not allow \(-17\) for magnitude
in the direction of \(P\)'s final travel oeB1 [3] Could be shown on diagram (may be seen in part (a)); away from the wall; ignore "towards P"
Part (c)
AnswerMarks Guidance
\(17\) (Ns)B1FT FT their magnitude of impulse from (b); positive value only, ignore units
in the opposite direction (to their previous direction) oeB1 [2] Direction of \(P\)'s initial travel; if "left" mentioned in part (a), then accept "right" as opposite direction; NB if \(I = 0\), then award B0B0
# Question 1:

## Part (a)
$e = \frac{0 - (-2.8)}{4 - 0} = 0.7$ | **B1** [1] | oe e.g. $\frac{2.8}{4} = 0.7$; B0 for $-0.7$

## Part (b)
Impulse on $P = \Delta mv = \pm(2.5 \times 4 - 2.5 \times (-2.8))$ | **M1** | Finding change in $P$'s momentum; allow 1 slip but not wrong sign inside brackets

$= 17$ (Ns) | **A1** | Do not allow $-17$ for magnitude

in the direction of $P$'s final travel oe | **B1** [3] | Could be shown on diagram (may be seen in part (a)); away from the wall; ignore "towards P"

## Part (c)
$17$ (Ns) | **B1FT** | FT their magnitude of impulse from **(b)**; positive value only, ignore units

in the opposite direction (to their previous direction) oe | **B1** [2] | Direction of $P$'s initial travel; if "left" mentioned in part (a), then accept "right" as opposite direction; NB if $I = 0$, then award B0B0

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1 A particle $P$ of mass 2.5 kg is moving with a constant speed of $4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ in a straight line on a smooth horizontal plane when it collides directly with a fixed vertical wall.

After the collision $P$ moves away from the wall with a speed of $2.8 \mathrm {~ms} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Calculate the coefficient of restitution between $P$ and the wall.
\item Find the magnitude and state the direction of the impulse exerted on $P$ by the wall.
\item State the magnitude and direction of the impulse exerted on the wall by $P$.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Mechanics AS 2024 Q1 [6]}}