OCR Further Pure Core AS Specimen — Question 2 4 marks

Exam BoardOCR
ModuleFurther Pure Core AS (Further Pure Core AS)
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeMultiplication and powers of complex numbers
DifficultyModerate -0.5 This is a straightforward Further Maths question testing basic complex number operations (conjugate multiplication and algebraic manipulation). While it's from Further Maths content, the operations are routine and mechanical with no conceptual challenges—just careful arithmetic. It's easier than an average A-level question overall due to its purely procedural nature, though the Further Maths context prevents it from being rated lower.
Spec4.02e Arithmetic of complex numbers: add, subtract, multiply, divide

2 In this question you must show detailed reasoning.
Given that \(z _ { 1 } = 3 + 2 \mathrm { i }\) and \(z _ { 2 } = - 1 - \mathrm { i }\), find the following, giving each in the form \(a + b \mathrm { i }\).
  1. \(z _ { 1 } ^ { * } z _ { 2 }\)
  2. \(\frac { z _ { 1 } + 2 z _ { 2 } } { z _ { 2 } }\)

Question 2(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(z_1^* z_2 = (3-2i)(-1-i) = -3+2i-3i+2i^2\)M1 (AO 1.1) Find conjugate, then multiply out brackets
\(= -5 - i\)A1 (AO 1.1)
[2]
Question 2(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\dfrac{z_1 + 2z_2}{z_2} = \dfrac{3+2i-2-2i}{-1-i} = \dfrac{1}{-1-i} \cdot \dfrac{-1+i}{-1+i}\)M1 (AO 1.1) Multiply by \(\dfrac{-1+i}{-1+i}\)
\(= \dfrac{-1+i}{2} = -\dfrac{1}{2} + \dfrac{1}{2}i\)A1 (AO 1.1)
[2]
# Question 2(i):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $z_1^* z_2 = (3-2i)(-1-i) = -3+2i-3i+2i^2$ | **M1** (AO 1.1) | Find conjugate, then multiply out brackets | Working must be seen |
| $= -5 - i$ | **A1** (AO 1.1) | |
| **[2]** | | |

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# Question 2(ii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\dfrac{z_1 + 2z_2}{z_2} = \dfrac{3+2i-2-2i}{-1-i} = \dfrac{1}{-1-i} \cdot \dfrac{-1+i}{-1+i}$ | **M1** (AO 1.1) | Multiply by $\dfrac{-1+i}{-1+i}$ | Must be seen |
| $= \dfrac{-1+i}{2} = -\dfrac{1}{2} + \dfrac{1}{2}i$ | **A1** (AO 1.1) | |
| **[2]** | | |

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2 In this question you must show detailed reasoning.\\
Given that $z _ { 1 } = 3 + 2 \mathrm { i }$ and $z _ { 2 } = - 1 - \mathrm { i }$, find the following, giving each in the form $a + b \mathrm { i }$.\\
(i) $z _ { 1 } ^ { * } z _ { 2 }$\\
(ii) $\frac { z _ { 1 } + 2 z _ { 2 } } { z _ { 2 } }$

\hfill \mbox{\textit{OCR Further Pure Core AS  Q2 [4]}}