Standard +0.3 This is a standard Further Maths question on transformed roots requiring Vieta's formulas and algebraic manipulation. Students need to find α+β=-2 and αβ=5, then compute α²+β²=(α+β)²-2αβ=4-10=-6 and α²β²=(αβ)²=25, giving p=6 and q=25. While it requires multiple steps and is from Further Maths content, it follows a well-practiced technique with no novel insight needed, making it slightly above average difficulty.
1 In this question you must show detailed reasoning.
The equation \(x ^ { 2 } + 2 x + 5 = 0\) has roots \(\alpha\) and \(\beta\). The equation \(x ^ { 2 } + p x + q = 0\) has roots \(\alpha ^ { 2 }\) and \(\beta ^ { 2 }\).
Find the values of \(p\) and \(q\).
1 In this question you must show detailed reasoning.\\
The equation $x ^ { 2 } + 2 x + 5 = 0$ has roots $\alpha$ and $\beta$. The equation $x ^ { 2 } + p x + q = 0$ has roots $\alpha ^ { 2 }$ and $\beta ^ { 2 }$.\\
Find the values of $p$ and $q$.
\hfill \mbox{\textit{OCR Further Pure Core AS Q1 [3]}}