OCR MEI Paper 2 2021 November — Question 1 2 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
Year2021
SessionNovember
Marks2
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeSingle transformation application
DifficultyEasy -1.2 This is a straightforward application of a single transformation rule (horizontal stretch with scale factor 2 means replacing x with x/2). It requires only substitution and algebraic expansion, with no problem-solving insight needed. The question is more routine than average A-level questions.
Spec1.02w Graph transformations: simple transformations of f(x)
1 The equation of a curve is \(y = 4 x ^ { 2 } + 8 x + 1\).
The curve is stretched parallel to the \(x\)-axis with scale factor 2 .
Find the equation of the new curve, giving your answer in the form \(\mathrm { y } = a \mathrm { x } ^ { 2 } + b \mathrm { x } + c\), where \(a , b\) and \(c\) are integers to be determined.
Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\((y =) 4(kx)^2 + 8(kx) + 1\) soiM1 \(k = \frac{1}{2}\); condone \(k = 2\); condone omission of brackets
\(y = x^2 + 4x + 1\) iswA1 must see "\(y =\)" either here or in first line
[2] 
## Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $(y =) 4(kx)^2 + 8(kx) + 1$ **soi** | M1 | $k = \frac{1}{2}$; condone $k = 2$; condone omission of brackets |
| $y = x^2 + 4x + 1$ **isw** | A1 | must see "$y =$" either here or in first line |
| | **[2]** | |

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1 The equation of a curve is $y = 4 x ^ { 2 } + 8 x + 1$.\\
The curve is stretched parallel to the $x$-axis with scale factor 2 .\\
Find the equation of the new curve, giving your answer in the form $\mathrm { y } = a \mathrm { x } ^ { 2 } + b \mathrm { x } + c$, where $a , b$ and $c$ are integers to be determined.

\hfill \mbox{\textit{OCR MEI Paper 2 2021 Q1 [2]}}
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Q1 2 Q2 3 Q3 3 Q4 3 Q5 3 Q6 5 Q7 4 Q8 4 Q9 10 Q10 9 Q11 8 Q12 5 Q13 7 Q14 13 Q15 11 Q16 8