OCR MEI Paper 2 2021 November — Question 8 4 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
Year2021
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear combinations of normal random variables
TypeLinear transformation to achieve target parameters
DifficultyStandard +0.3 This is a straightforward application of linear transformation properties for normal distributions: E(Y) = a + bE(X) and Var(Y) = b²Var(X). Students need to set up two equations and solve simultaneously, requiring only algebraic manipulation of given parameters. While it involves Further Maths content, the problem is routine and mechanical once the transformation rules are recalled.
Spec2.04d Normal approximation to binomial2.04e Normal distribution: as model N(mu, sigma^2)

8 The Normal variable \(X\) is transformed to the Normal variable \(Y\).
The transformation is \(\mathrm { y } = \mathrm { a } + \mathrm { bx }\), where \(a\) and \(b\) are positive constants.
You are given that \(X \sim N ( 42,6.8 )\) and \(Y \sim N ( 57.2,11.492 )\).
Determine the values of \(a\) and \(b\).

Question 8:
AnswerMarks Guidance
AnswerMarks Guidance
\(b^2 = \frac{11.492}{6.8}\) oeM1
\(b = 1.3\)A1
\(42b + a = 57.2\)M1 \(b\) may be incorrect numerical value
\(a = 2.6\)A1
[4]
## Question 8:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $b^2 = \frac{11.492}{6.8}$ **oe** | M1 | |
| $b = 1.3$ | A1 | |
| $42b + a = 57.2$ | M1 | $b$ may be incorrect numerical value |
| $a = 2.6$ | A1 | |
| | **[4]** | |

---
8 The Normal variable $X$ is transformed to the Normal variable $Y$.\\
The transformation is $\mathrm { y } = \mathrm { a } + \mathrm { bx }$, where $a$ and $b$ are positive constants.\\
You are given that $X \sim N ( 42,6.8 )$ and $Y \sim N ( 57.2,11.492 )$.\\
Determine the values of $a$ and $b$.

\hfill \mbox{\textit{OCR MEI Paper 2 2021 Q8 [4]}}