| Exam Board | OCR MEI |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2018 |
| Session | June |
| Marks | 2 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Probability Definitions |
| Type | Basic probability calculation |
| Difficulty | Easy -1.8 This is a very straightforward probability question requiring only basic understanding that P(not W) = 1 - 0.4 = 0.6, then squaring for two matches (0.36), and recognizing that draws exist in football so W and L aren't complementary events. No problem-solving or multi-step reasoning needed—pure recall and simple arithmetic. |
| Spec | 2.03a Mutually exclusive and independent events |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(0.36\) | B1 (AO1.1) | |
| [1] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(P(\text{draw})\neq 0\) oe | B1 (AO2.4) | Allow any comment which identifies that other outcomes are possible; e.g. winning and losing are not exhaustive |
| [1] |
## Question 3(i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $0.36$ | B1 (AO1.1) | |
| **[1]** | | |
## Question 3(ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $P(\text{draw})\neq 0$ oe | B1 (AO2.4) | Allow any comment which identifies that other outcomes are possible; e.g. winning and losing are not exhaustive |
| **[1]** | | |
---3 The probability that Chipping FC win a league football match is $\mathrm { P } ( W ) = 0.4$.\\
(i) Calculate the probability that Chipping FC fail to win each of their next two league football matches.
The probability that Chipping FC lose a league football match is $\mathrm { P } ( L ) = 0.3$.\\
(ii) Explain why $\mathrm { P } ( W ) + \mathrm { P } ( L ) \neq 1$.
\hfill \mbox{\textit{OCR MEI Paper 2 2018 Q3 [2]}}