OCR MEI Paper 2 2018 June — Question 2 3 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
Year2018
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSolve |linear| < constant (pure inequality)
DifficultyEasy -1.8 This is a straightforward application of the basic modulus inequality rule |ax + b| < c ⟹ -c < ax + b < c, requiring only simple algebraic manipulation to solve. It's a routine textbook exercise testing recall of a standard technique with minimal steps, making it significantly easier than average A-level questions.
Spec1.02l Modulus function: notation, relations, equations and inequalities
2 Solve the inequality \(| 2 x + 1 | < 5\).
Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\(-5 < 2x+1 < 5\)M1 (AO2.1) \(-(2x+1)<5\) oe and \(2x+1<5\); or \((2x+1)^2<25\)
\(-6 < 2x < 4\)A1 (AO1.1) \(-3\) and \(2\) identified; if M0 allow B1 for either condition identified
\(-3 < x < 2\)A1 (AO1.1) \(-3-3\) and \(x<2\)
[3] 
## Question 2:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $-5 < 2x+1 < 5$ | M1 (AO2.1) | $-(2x+1)<5$ oe and $2x+1<5$; or $(2x+1)^2<25$ |
| $-6 < 2x < 4$ | A1 (AO1.1) | $-3$ and $2$ identified; if M0 allow B1 for either condition identified |
| $-3 < x < 2$ | A1 (AO1.1) | $-3<x<2$; allow $x>-3$ **and** $x<2$ |
| **[3]** | | |

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2 Solve the inequality $| 2 x + 1 | < 5$.

\hfill \mbox{\textit{OCR MEI Paper 2 2018 Q2 [3]}}
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Q1 2 Q2 3 Q3 2 Q4 2 Q5 3 Q6 5 Q7 4 Q8 4 Q9 5 Q10 8 Q11 6 Q12 5 Q13 10 Q14 9 Q15 9 Q16 11 Q17 12