OCR MEI Paper 2 2018 June — Question 1 2 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
Year2018
SessionJune
Marks2
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeShow surd expression equals value
DifficultyEasy -1.8 This is a routine surd simplification requiring only basic factorization of 27 and 192 into prime factors, then applying √(mn)=√m×√n. It's a straightforward recall exercise with no problem-solving element, simpler than typical A-level questions.
Spec1.02b Surds: manipulation and rationalising denominators

1 Show that \(\sqrt { 27 } + \sqrt { 192 } = a \sqrt { b }\), where \(a\) and \(b\) are prime numbers to be determined.

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(3\sqrt{3}\) or \(8\sqrt{3}\) seenM1 (AO1.1)
\([3\sqrt{3}+8\sqrt{3}=]11\sqrt{3}\)A1 (AO2.1)
[2]
## Question 1:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $3\sqrt{3}$ or $8\sqrt{3}$ seen | M1 (AO1.1) | |
| $[3\sqrt{3}+8\sqrt{3}=]11\sqrt{3}$ | A1 (AO2.1) | |
| **[2]** | | |

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1 Show that $\sqrt { 27 } + \sqrt { 192 } = a \sqrt { b }$, where $a$ and $b$ are prime numbers to be determined.

\hfill \mbox{\textit{OCR MEI Paper 2 2018 Q1 [2]}}