OCR MEI Paper 1 2024 June — Question 14 7 marks

Exam BoardOCR MEI
ModulePaper 1 (Paper 1)
Year2024
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeProjectile motion: trajectory equation
DifficultyStandard +0.3 This is a standard 2D projectile motion problem with straightforward application of SUVAT equations. Part (a) is bookwork, part (b) requires one vertical equation with given values, and part (c) involves finding horizontal component then using Pythagoras. All steps are routine with no conceptual challenges beyond basic projectile mechanics.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

14 A man runs at a constant speed of \(4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) along a straight horizontal road. A woman is standing on a bridge that spans the road. At the instant that the man passes directly below the woman she throws a ball with initial speed \(u \mathrm {~ms} ^ { - 1 }\) at \(\alpha ^ { \circ }\) above the horizontal. The path of the ball is directly above the road. The man catches the ball 2.4 s after it is thrown. At the instant the man catches it, the ball is 3.6 m below the level of the point of projection.
  1. Explain what it means that the ball is modelled as a particle.
  2. Find the vertical component of the ball's initial velocity.
  3. Find each of the following.

Question 14(a) — Exemplar responses:
AnswerMarks
ResponseMark
The mass is concentrated at the centreB0
The object has no massB0
There is no air resistanceB0
The weight acts at the centre [of mass]B0
There is no spinB1
The ball's size and shape do not matterB1
Only its mass is taken into account so it doesn't spinB1
The size of the ball is negligible and there are no external forces acting on the ballB0
Point mass means there is no air resistanceB0
There is no air resistance because the object has no sizeB0
## Question 14(a) — Exemplar responses:

| Response | Mark |
|---|---|
| The mass is concentrated at the centre | **B0** |
| The object has no mass | **B0** |
| There is no air resistance | **B0** |
| The weight acts at the centre [of mass] | **B0** |
| There is no spin | **B1** |
| The ball's size and shape do not matter | **B1** |
| Only its mass is taken into account so it doesn't spin | **B1** |
| The size of the ball is negligible and there are no external forces acting on the ball | **B0** |
| Point mass means there is no air resistance | **B0** |
| There is no air resistance because the object has no size | **B0** |
14 A man runs at a constant speed of $4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ along a straight horizontal road. A woman is standing on a bridge that spans the road. At the instant that the man passes directly below the woman she throws a ball with initial speed $u \mathrm {~ms} ^ { - 1 }$ at $\alpha ^ { \circ }$ above the horizontal. The path of the ball is directly above the road. The man catches the ball 2.4 s after it is thrown. At the instant the man catches it, the ball is 3.6 m below the level of the point of projection.
\begin{enumerate}[label=(\alph*)]
\item Explain what it means that the ball is modelled as a particle.
\item Find the vertical component of the ball's initial velocity.
\item Find each of the following.

\begin{itemize}
  \item The value of $u$
  \item The value of $\alpha$
\end{itemize}
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 1 2024 Q14 [7]}}