| Exam Board | OCR MEI |
|---|---|
| Module | Paper 1 (Paper 1) |
| Year | 2024 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Projectile motion: trajectory equation |
| Difficulty | Standard +0.3 This is a standard 2D projectile motion problem with straightforward application of SUVAT equations. Part (a) is bookwork, part (b) requires one vertical equation with given values, and part (c) involves finding horizontal component then using Pythagoras. All steps are routine with no conceptual challenges beyond basic projectile mechanics. |
| Spec | 3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model |
| Answer | Marks |
|---|---|
| Response | Mark |
| The mass is concentrated at the centre | B0 |
| The object has no mass | B0 |
| There is no air resistance | B0 |
| The weight acts at the centre [of mass] | B0 |
| There is no spin | B1 |
| The ball's size and shape do not matter | B1 |
| Only its mass is taken into account so it doesn't spin | B1 |
| The size of the ball is negligible and there are no external forces acting on the ball | B0 |
| Point mass means there is no air resistance | B0 |
| There is no air resistance because the object has no size | B0 |
## Question 14(a) — Exemplar responses:
| Response | Mark |
|---|---|
| The mass is concentrated at the centre | **B0** |
| The object has no mass | **B0** |
| There is no air resistance | **B0** |
| The weight acts at the centre [of mass] | **B0** |
| There is no spin | **B1** |
| The ball's size and shape do not matter | **B1** |
| Only its mass is taken into account so it doesn't spin | **B1** |
| The size of the ball is negligible and there are no external forces acting on the ball | **B0** |
| Point mass means there is no air resistance | **B0** |
| There is no air resistance because the object has no size | **B0** |
14 A man runs at a constant speed of $4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ along a straight horizontal road. A woman is standing on a bridge that spans the road. At the instant that the man passes directly below the woman she throws a ball with initial speed $u \mathrm {~ms} ^ { - 1 }$ at $\alpha ^ { \circ }$ above the horizontal. The path of the ball is directly above the road. The man catches the ball 2.4 s after it is thrown. At the instant the man catches it, the ball is 3.6 m below the level of the point of projection.
\begin{enumerate}[label=(\alph*)]
\item Explain what it means that the ball is modelled as a particle.
\item Find the vertical component of the ball's initial velocity.
\item Find each of the following.
\begin{itemize}
\item The value of $u$
\item The value of $\alpha$
\end{itemize}
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Paper 1 2024 Q14 [7]}}