OCR MEI Paper 1 2023 June — Question 3 3 marks

Exam BoardOCR MEI
ModulePaper 1 (Paper 1)
Year2023
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind indefinite integral of polynomial/power
DifficultyEasy -1.2 This is a straightforward integration of polynomial terms requiring only basic power rule application. Students need to rewrite √x as x^(1/2), combine powers, then integrate using the standard formula x^n → x^(n+1)/(n+1). No problem-solving or conceptual insight required—purely routine manipulation below average difficulty.
Spec1.08b Integrate x^n: where n != -1 and sums

3 Find \(\int \left( 2 x ^ { 4 } - x \sqrt { x } \right) d x\).

Question 3:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\int(2x^4 - x\sqrt{x})\,dx = \int\left(2x^4 - x^{\frac{3}{2}}\right)dx\)M1 Expresses integrand in index form
\(\frac{2x^5}{5} - \frac{x^{5/2}}{5/2} \left[+c\right]\)M1 Integrates at least one term
\(\frac{2x^5}{5} - \frac{2x^{\frac{5}{2}}}{5} + c\)A1 Any form. Arbitrary constant must be seen. Correct answer for the second term by a different method implies the first M1
Total: [3]
## Question 3:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\int(2x^4 - x\sqrt{x})\,dx = \int\left(2x^4 - x^{\frac{3}{2}}\right)dx$ | M1 | Expresses integrand in index form |
| $\frac{2x^5}{5} - \frac{x^{5/2}}{5/2} \left[+c\right]$ | M1 | Integrates at least one term |
| $\frac{2x^5}{5} - \frac{2x^{\frac{5}{2}}}{5} + c$ | A1 | Any form. Arbitrary constant must be seen. Correct answer for the second term by a different method implies the first M1 |

**Total: [3]**
3 Find $\int \left( 2 x ^ { 4 } - x \sqrt { x } \right) d x$.

\hfill \mbox{\textit{OCR MEI Paper 1 2023 Q3 [3]}}