OCR MEI AS Paper 2 2023 June — Question 9 6 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
Year2023
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Probability Distributions
TypeOne unknown from sum constraint only
DifficultyEasy -1.3 This is a straightforward probability distribution question requiring only basic recall and routine calculations: (a) uses the sum-to-1 constraint to find q algebraically, (b) is simple addition, (c) applies independence with P(X=1)×P(X=2)×2, and (d) is a standard binomial probability calculation. All parts are textbook exercises with no problem-solving or novel insight required.
Spec2.04a Discrete probability distributions2.04c Calculate binomial probabilities

9 The table shows the probability distribution for the discrete random variable \(X\).
\(x\)12345
\(\mathrm { P } ( \mathrm { X } = \mathrm { x } )\)0.10.3\(q\)\(2 q\)\(3 q\)
You are given that \(q\) is a positive constant.
  1. Determine the value of \(q\).
  2. Calculate \(\mathrm { P } ( X \leqslant 4 )\). Two independent values of \(X\) are taken.
  3. Determine the probability that the sum of the two values is 3 . Fifty independent values of \(X\) are taken.
  4. Find the probability that a value of 2 occurs exactly 17 times.

Question 9:
Part (a):
AnswerMarks Guidance
\(0.1 + 0.3 + q + 2q + 3q = 1\)M1 Setting sum of values equal to 1
\(q = 0.1\)A1
Part (b):
AnswerMarks Guidance
\((0.1 + 0.3 + 0.1 + 0.2 =)\ 0.7\)B1 Or \(1 - p(X=5)\)
Part (c):
AnswerMarks Guidance
\(0.1 \times 0.3\) seen or \(0.03\) seenM1
\(0.1 \times 0.3 + 0.1 \times 0.3 = 0.06\)A1 \(0.06\) o.e. \(\frac{6}{100}\) or \(\frac{3}{50}\) etc
Part (d):
AnswerMarks Guidance
\(0.098314\ldots\) correct to 2 or more sfB1 By using e.g. \(X \sim B(50, 0.3)\) and finding \(P(X=17)\)
## Question 9:

### Part (a):
$0.1 + 0.3 + q + 2q + 3q = 1$ | **M1** | Setting sum of values equal to 1
$q = 0.1$ | **A1** |

### Part (b):
$(0.1 + 0.3 + 0.1 + 0.2 =)\ 0.7$ | **B1** | Or $1 - p(X=5)$

### Part (c):
$0.1 \times 0.3$ seen or $0.03$ seen | **M1** |
$0.1 \times 0.3 + 0.1 \times 0.3 = 0.06$ | **A1** | $0.06$ o.e. $\frac{6}{100}$ or $\frac{3}{50}$ etc

### Part (d):
$0.098314\ldots$ correct to 2 or more sf | **B1** | By using e.g. $X \sim B(50, 0.3)$ and finding $P(X=17)$

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9 The table shows the probability distribution for the discrete random variable $X$.

\begin{center}
\begin{tabular}{ | l | l | l | l | l | l | }
\hline
$x$ & 1 & 2 & 3 & 4 & 5 \\
\hline
$\mathrm { P } ( \mathrm { X } = \mathrm { x } )$ & 0.1 & 0.3 & $q$ & $2 q$ & $3 q$ \\
\hline
\end{tabular}
\end{center}

You are given that $q$ is a positive constant.
\begin{enumerate}[label=(\alph*)]
\item Determine the value of $q$.
\item Calculate $\mathrm { P } ( X \leqslant 4 )$.

Two independent values of $X$ are taken.
\item Determine the probability that the sum of the two values is 3 .

Fifty independent values of $X$ are taken.
\item Find the probability that a value of 2 occurs exactly 17 times.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 2 2023 Q9 [6]}}