OCR MEI AS Paper 2 2023 June — Question 1 3 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
Year2023
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeVertical line chart construction
DifficultyEasy -1.8 This is a straightforward AS-level statistics question requiring basic critique of a graph representation and routine calculations of mean and standard deviation from a frequency table. Part (a) requires recognizing that discrete data shouldn't be shown with a continuous representation (likely a line graph or histogram), while part (b) involves standard formula application with no problem-solving or conceptual challenge beyond basic statistical literacy.
Spec2.02a Interpret single variable data: tables and diagrams2.02f Measures of average and spread2.02g Calculate mean and standard deviation

1 A researcher collects data concerning the number of different social media platforms used by school pupils on a typical weekday. The frequency table for the data is shown below.
Number of different social media platforms01234567
Frequency259158541
The researcher uses software to represent the results in this diagram. \includegraphics[max width=\textwidth, alt={}, center]{82438df0-6550-4ffd-92d8-3c67bec59a6b-04_961_1195_737_242}
  1. Explain why this diagram is inappropriate.
  2. Calculate the following for the number of social media platforms used:
    1. the mean,
    2. the standard deviation.

Question 1:
Part (a)
AnswerMarks Guidance
The given data (on the graph) is continuous, not discreteE1 Need a comment on the suitability of the histogram for the given data – must comment on the type(s) of data. The data is discrete so there should be gaps between the bars / histogram uses ranges e.g. 6-7 but data is discrete and cannot have values between 6-7
Part (b)(i)
AnswerMarks Guidance
\(3.183\ldots\) to \(3.184\) or \(3.18\)B1 Exact value is \(3.183673469\) or \(3\frac{9}{49}\) or \(\frac{156}{49}\). Allow if seen in (b)(ii). SC: 3.2 allow B1
Part (b)(ii)
AnswerMarks Guidance
\(1.61\ldots\) to \(1.62\) OR \(1.59\ldots\) to \(1.60\)B1 Exact value is \(1.615980989\) (sample). Exact value is \(1.599406387\) (population)
# Question 1:

## Part (a)
The given data (on the graph) is continuous, not discrete | E1 | Need a comment on the suitability of the histogram for the given data – must comment on the type(s) of data. The data is discrete so there should be gaps between the bars / histogram uses ranges e.g. 6-7 but data is discrete and cannot have values between 6-7

## Part (b)(i)
$3.183\ldots$ to $3.184$ or $3.18$ | B1 | Exact value is $3.183673469$ or $3\frac{9}{49}$ or $\frac{156}{49}$. Allow if seen in (b)(ii). SC: 3.2 allow B1

## Part (b)(ii)
$1.61\ldots$ to $1.62$ OR $1.59\ldots$ to $1.60$ | B1 | Exact value is $1.615980989$ (sample). Exact value is $1.599406387$ (population)

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1 A researcher collects data concerning the number of different social media platforms used by school pupils on a typical weekday.

The frequency table for the data is shown below.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | c | c | c | c | }
\hline
Number of different social media platforms & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\
\hline
Frequency & 2 & 5 & 9 & 15 & 8 & 5 & 4 & 1 \\
\hline
\end{tabular}
\end{center}

The researcher uses software to represent the results in this diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{82438df0-6550-4ffd-92d8-3c67bec59a6b-04_961_1195_737_242}
\begin{enumerate}[label=(\alph*)]
\item Explain why this diagram is inappropriate.
\item Calculate the following for the number of social media platforms used:
\begin{enumerate}[label=(\roman*)]
\item the mean,
\item the standard deviation.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 2 2023 Q1 [3]}}