OCR MEI AS Paper 2 2019 June — Question 4 3 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
Year2019
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircles
TypeFind centre and radius from equation
DifficultyEasy -1.2 This is a straightforward completing-the-square exercise to convert a circle equation to standard form. It requires only routine algebraic manipulation with no problem-solving or geometric insight, making it easier than average but not trivial since students must correctly complete the square for both variables.
Spec1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

4 The equation of a circle is \(x ^ { 2 } + y ^ { 2 } + 8 x - 6 y - 39 = 0\).
  1. Find the coordinates of the centre of the circle.
  2. Find the radius of the circle.

Question 4(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\((x \pm 4)^2\) and \((y \pm 3)^2\) seenM1 (3.1a) \((x+4)^2 - 4^2 + (y-3)^2 - (-3)^2 - 39 = 0\) www
centre is \((-4, 3)\)A1 (1.1)
[2]
## Question 4(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $(x \pm 4)^2$ and $(y \pm 3)^2$ seen | M1 (3.1a) | $(x+4)^2 - 4^2 + (y-3)^2 - (-3)^2 - 39 = 0$ www |
| centre is $(-4, 3)$ | A1 (1.1) | |
| **[2]** | | |
4 The equation of a circle is $x ^ { 2 } + y ^ { 2 } + 8 x - 6 y - 39 = 0$.
\begin{enumerate}[label=(\alph*)]
\item Find the coordinates of the centre of the circle.
\item Find the radius of the circle.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 2 2019 Q4 [3]}}