| Exam Board | OCR MEI |
|---|---|
| Module | AS Paper 2 (AS Paper 2) |
| Year | 2019 |
| Session | June |
| Marks | 2 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Sine and Cosine Rules |
| Type | Triangle area calculation |
| Difficulty | Moderate -0.8 This is a straightforward application of the triangle area formula (1/2)ab sin C with two sides and the included angle directly given. It requires only substitution into a standard formula and calculator work, making it easier than average with no problem-solving or multi-step reasoning required. |
| Spec | 1.05c Area of triangle: using 1/2 ab sin(C) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(\frac{1}{2} \times 14 \times 8 \sin 117°\) | M1 (1.2) | Condone omission of \(\frac{1}{2}\) |
| \(49.9 \text{ [cm}^2\text{]}\) | A1 | Accept 50. 50.0 is wrong |
| [2] |
## Question 2:
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\frac{1}{2} \times 14 \times 8 \sin 117°$ | M1 (1.2) | Condone omission of $\frac{1}{2}$ |
| $49.9 \text{ [cm}^2\text{]}$ | A1 | Accept 50. 50.0 is wrong |
| **[2]** | | |2 Fig. 2 shows a triangle with one angle of $117 ^ { \circ }$ given. The lengths are given in centimetres.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{11e5167f-9f95-4494-9b66-b59fdce8b1ef-3_300_791_589_244}
\captionsetup{labelformat=empty}
\caption{Fig. 2}
\end{center}
\end{figure}
Calculate the area of the triangle, giving your answer correct to 3 significant figures.
\hfill \mbox{\textit{OCR MEI AS Paper 2 2019 Q2 [2]}}