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LFM Pure
Product & Quotient Rules
Q14
Edexcel Paper 1 2021 October — Question 14
Exam Board
Edexcel
Module
Paper 1 (Paper 1)
Year
2021
Session
October
Topic
Product & Quotient Rules
Given that
$$y = \frac { x - 4 } { 2 + \sqrt { x } } \quad x > 0$$ show that $$\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 1 } { \mathrm {~A} \sqrt { \mathrm { x } } } \quad x > 0$$ where \(A\) is a constant to be found.
VIIV SIHI NI III HM IONOO
VIAV SIHI NI III M M I O N OO
VIUV SIHI NI IIIUM ION OC
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