Edexcel PMT Mocks — Question 13 6 marks

Exam BoardEdexcel
ModulePMT Mocks (PMT Mocks)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors 3D & Lines
TypeCollinearity and ratio division
DifficultyStandard +0.3 Part (a) is a standard collinearity problem requiring students to use the direction vector PQ and apply it to find m—straightforward vector arithmetic. Part (b) involves finding point T using parallel vector conditions and computing magnitude, requiring more steps but still following routine procedures. This is slightly easier than average as it's methodical application of standard vector techniques without requiring novel insight.
Spec1.10b Vectors in 3D: i,j,k notation1.10e Position vectors: and displacement1.10f Distance between points: using position vectors

13. Relative to a fixed origin \(O\)
  • the point \(P\) has position vector \(( 0 , - 1,2 )\)
  • the point \(Q\) has position vector \(( 1,1,5 )\)
  • the point \(R\) has position vector ( \(3,5 , m\) )
    where \(m\) is a constant.
    Given that \(P , Q\) and \(R\) lie on a straight line,
    a. find the value of \(m\)
The line segment \(O Q\) is extended to a point \(T\) so that \(\overrightarrow { R T }\) is parallel to \(\overrightarrow { O P }\) b. Show that \(| \overrightarrow { O T } | = 9 \sqrt { 3 }\).

(6 marks)
AnswerMarks
M1Attempts two of the three relevant vectors by subtracting either way round. Example: \(\pm\overrightarrow{PQ} = \pm(i + 2j + 3k)\) or \(\pm\overrightarrow{PR} = \pm(3i + 6j + (m - 2)k)\) or \(\pm\overrightarrow{QR} = \pm(2i + 4j + (m - 5)k)\)
dM1For the key step in using the fact that if the vectors are parallel, they will be multiples of each other to find m. Example: \(\overrightarrow{QR} = 2\overrightarrow{PQ}\) so \(m - 5 = 2 \times 3\); $\overrightarrow{PR} = 3\overrightar
(6 marks)

**M1** | Attempts two of the three relevant vectors by subtracting either way round. Example: $\pm\overrightarrow{PQ} = \pm(i + 2j + 3k)$ or $\pm\overrightarrow{PR} = \pm(3i + 6j + (m - 2)k)$ or $\pm\overrightarrow{QR} = \pm(2i + 4j + (m - 5)k)$

**dM1** | For the key step in using the fact that if the vectors are parallel, they will be multiples of each other to find m. Example: $\overrightarrow{QR} = 2\overrightarrow{PQ}$ so $m - 5 = 2 \times 3$; $\overrightarrow{PR} = 3\overrightar
13. Relative to a fixed origin $O$

\begin{itemize}
  \item the point $P$ has position vector $( 0 , - 1,2 )$
  \item the point $Q$ has position vector $( 1,1,5 )$
  \item the point $R$ has position vector ( $3,5 , m$ )\\
where $m$ is a constant.\\
Given that $P , Q$ and $R$ lie on a straight line,\\
a. find the value of $m$
\end{itemize}

The line segment $O Q$ is extended to a point $T$ so that $\overrightarrow { R T }$ is parallel to $\overrightarrow { O P }$\\
b. Show that $| \overrightarrow { O T } | = 9 \sqrt { 3 }$.\\

\hfill \mbox{\textit{Edexcel PMT Mocks  Q13 [6]}}