AQA D2 2010 June — Question 1 13 marks

Exam BoardAQA
ModuleD2 (Decision Mathematics 2)
Year2010
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCritical Path Analysis
TypeEffect of activity delay/change
DifficultyModerate -0.8 This is a standard Critical Path Analysis question testing routine algorithmic procedures (forward/backward pass, identifying critical paths, drawing Gantt charts, and analyzing simple delays). While multi-part, each component follows textbook methods with no novel problem-solving required, making it easier than average A-level material.
Spec7.05a Critical path analysis: activity on arc networks7.05b Forward and backward pass: earliest/latest times, critical activities7.05c Total float: calculation and interpretation7.05d Latest start and earliest finish: independent and interfering float7.05e Cascade charts: scheduling and effect of delays

1 Figure 1 below shows an activity diagram for a construction project. The time needed for each activity is given in days.
  1. Find the earliest start time and latest finish time for each activity and insert their values on Figure 1.
  2. Find the critical paths and state the minimum time for completion of the project.
  3. On Figure 2 opposite, draw a cascade diagram (Gantt chart) for the project, assuming that each activity starts as early as possible.
  4. A delay in supplies means that Activity \(I\) takes 9 days instead of 2 .
    1. Determine the effect on the earliest possible starting times for activities \(K\) and \(L\).
    2. State the number of days by which the completion of the project is now delayed.
      (1 mark) \section*{Figure 1}
      1. \includegraphics[max width=\textwidth, alt={}, center]{c4dc61a7-47ee-4d5c-bf6d-30a5da2ee8dd-02_815_1337_1573_395}
      2. Critical paths are \(\_\_\_\_\) Minimum completion time is \(\_\_\_\_\) days. QUESTION PART REFERENCE
      3. \begin{figure}[h]
        \captionsetup{labelformat=empty} \caption{Figure 2} \includegraphics[alt={},max width=\textwidth]{c4dc61a7-47ee-4d5c-bf6d-30a5da2ee8dd-03_978_1207_354_461}
        \end{figure}

Question 1:
Part (a)
AnswerMarks Guidance
AnswerMarks Guidance
Forward pass: EST for node after A = 4, after B = 3, after C = 2B1
EST for D = 4, E = max(4,3) = 4 (not 3), F = max(3,2) = 3M1 Method for finding ESTs correctly
ESTs: G = 7, H = 8, I = 8; J = 15, K = 14, L = 17; Project = 19A1 All ESTs correct
Latest finish times found by backward pass; LFT = 19 throughout critical pathA1 All LFTs correct
Part (b)
AnswerMarks Guidance
AnswerMarks Guidance
Critical path: \(B \to E \to H \to J \to L\)B1
Critical path: \(B \to E \to H \to K \to L\)B1
Minimum completion time = 19 daysB1
Part (c)
AnswerMarks Guidance
AnswerMarks Guidance
Activities labelled correctly on Gantt chartB1
All activities starting at correct earliest start timesB1
All durations correctB1
Part (d)(i)
AnswerMarks Guidance
AnswerMarks Guidance
Activity \(I\) now takes 9 days, so earliest finish of \(I\) = \(8 + 9 = 17\)M1
Earliest start of \(K\) = 17, earliest start of \(L\) = max(17+5, 15+2) = 22A1 Both correct
Part (d)(ii)
AnswerMarks Guidance
AnswerMarks Guidance
Project delayed by 3 days (completion now 22 days)B1
# Question 1:

## Part (a)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Forward pass: EST for node after A = 4, after B = 3, after C = 2 | B1 | |
| EST for D = 4, E = max(4,3) = 4 (not 3), F = max(3,2) = 3 | M1 | Method for finding ESTs correctly |
| ESTs: G = 7, H = 8, I = 8; J = 15, K = 14, L = 17; Project = 19 | A1 | All ESTs correct |
| Latest finish times found by backward pass; LFT = 19 throughout critical path | A1 | All LFTs correct |

## Part (b)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Critical path: $B \to E \to H \to J \to L$ | B1 | |
| Critical path: $B \to E \to H \to K \to L$ | B1 | |
| Minimum completion time = 19 days | B1 | |

## Part (c)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Activities labelled correctly on Gantt chart | B1 | |
| All activities starting at correct earliest start times | B1 | |
| All durations correct | B1 | |

## Part (d)(i)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Activity $I$ now takes 9 days, so earliest finish of $I$ = $8 + 9 = 17$ | M1 | |
| Earliest start of $K$ = 17, earliest start of $L$ = max(17+5, 15+2) = 22 | A1 | Both correct |

## Part (d)(ii)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Project delayed by 3 days (completion now 22 days) | B1 | |

---
1 Figure 1 below shows an activity diagram for a construction project. The time needed for each activity is given in days.
\begin{enumerate}[label=(\alph*)]
\item Find the earliest start time and latest finish time for each activity and insert their values on Figure 1.
\item Find the critical paths and state the minimum time for completion of the project.
\item On Figure 2 opposite, draw a cascade diagram (Gantt chart) for the project, assuming that each activity starts as early as possible.
\item A delay in supplies means that Activity $I$ takes 9 days instead of 2 .
\begin{enumerate}[label=(\roman*)]
\item Determine the effect on the earliest possible starting times for activities $K$ and $L$.
\item State the number of days by which the completion of the project is now delayed.\\
(1 mark)

\section*{Figure 1}
(a)\\
\includegraphics[max width=\textwidth, alt={}, center]{c4dc61a7-47ee-4d5c-bf6d-30a5da2ee8dd-02_815_1337_1573_395}\\
(b) Critical paths are $\_\_\_\_$\\

Minimum completion time is $\_\_\_\_$ days.

QUESTION PART REFERENCE\\
(c)

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 2}
  \includegraphics[alt={},max width=\textwidth]{c4dc61a7-47ee-4d5c-bf6d-30a5da2ee8dd-03_978_1207_354_461}
\end{center}
\end{figure}
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA D2 2010 Q1 [13]}}