CAIE P3 2011 November — Question 9

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2011
SessionNovember
TopicVectors: Cross Product & Distances

9 The line \(l\) has equation \(\mathbf { r } = \left( \begin{array} { l } a
1
4 \end{array} \right) + \lambda \left( \begin{array} { r } 4
3
- 2 \end{array} \right)\), where \(a\) is a constant. The plane \(p\) has equation \(2 x - 2 y + z = 10\).
  1. Given that \(l\) does not lie in \(p\), show that \(l\) is parallel to \(p\).
  2. Find the value of \(a\) for which \(l\) lies in \(p\).
  3. It is now given that the distance between \(l\) and \(p\) is 6 . Find the possible values of \(a\).