CAIE P3 2011 November — Question 3 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2011
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard two-part harmonic form question requiring routine application of the R cos(θ - α) formula (finding R and α using Pythagorean theorem and arctan), followed by solving a straightforward trigonometric equation. While it involves multiple steps, the techniques are well-practiced and require no novel insight, making it slightly easier than average.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

3
  1. Express \(8 \cos \theta + 15 \sin \theta\) in the form \(R \cos ( \theta - \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\). Give the value of \(\alpha\) correct to 2 decimal places.
  2. Hence solve the equation \(8 \cos \theta + 15 \sin \theta = 12\), giving all solutions in the interval \(0 ^ { \circ } < \theta < 360 ^ { \circ }\).

Question 3:
AnswerMarks Guidance
Answer/WorkingMark Guidance
(i) State or imply \(R = 17\)B1
Use correct trigonometric formula to find \(\alpha\)M1
Obtain \(61.93°\) with no errors seenA1 [3]
(ii) Evaluate \(\cos^{-1}\frac{12}{R}\) \((= 45.099°)\)M1
Obtain answer \(107.0°\)A1
Carry out correct method for second answerM1
Obtain answer \(16.8°\) and no others between \(0°\) and \(360°\)A1 [4]
## Question 3:

| Answer/Working | Mark | Guidance |
|---|---|---|
| **(i)** State or imply $R = 17$ | B1 | |
| Use correct trigonometric formula to find $\alpha$ | M1 | |
| Obtain $61.93°$ with no errors seen | A1 | [3] |
| **(ii)** Evaluate $\cos^{-1}\frac{12}{R}$ $(= 45.099°)$ | M1 | |
| Obtain answer $107.0°$ | A1 | |
| Carry out correct method for second answer | M1 | |
| Obtain answer $16.8°$ and no others between $0°$ and $360°$ | A1 | [4] |

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3 (i) Express $8 \cos \theta + 15 \sin \theta$ in the form $R \cos ( \theta - \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$. Give the value of $\alpha$ correct to 2 decimal places.\\
(ii) Hence solve the equation $8 \cos \theta + 15 \sin \theta = 12$, giving all solutions in the interval $0 ^ { \circ } < \theta < 360 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P3 2011 Q3 [7]}}