AQA FP3 2009 June — Question 1 6 marks

Exam BoardAQA
ModuleFP3 (Further Pure Mathematics 3)
Year2009
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeApply basic Euler method for differential equations
DifficultyStandard +0.3 This is a straightforward application of two standard numerical methods (Euler's method and midpoint method) with given formulas. Students simply substitute values into provided formulas requiring only arithmetic and one square root calculation per step. No derivation, proof, or problem-solving insight needed—purely procedural execution, making it slightly easier than average.
Spec1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

1 The function \(y ( x )\) satisfies the differential equation $$\frac { \mathrm { d } y } { \mathrm {~d} x } = \mathrm { f } ( x , y )$$ where $$\mathrm { f } ( x , y ) = \sqrt { x ^ { 2 } + y + 1 }$$ and $$y ( 3 ) = 2$$
  1. Use the Euler formula $$y _ { r + 1 } = y _ { r } + h \mathrm { f } \left( x _ { r } , y _ { r } \right)$$ with \(h = 0.1\), to obtain an approximation to \(y ( 3.1 )\), giving your answer to four decimal places.
  2. Use the formula $$y _ { r + 1 } = y _ { r - 1 } + 2 h \mathrm { f } \left( x _ { r } , y _ { r } \right)$$ with your answer to part (a), to obtain an approximation to \(y ( 3.2 )\), giving your answer to three decimal places.

Question 1:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y(3.1) = y(3) + 0.1\sqrt{3^2 + 2 + 1}\)M1A1
\(= 2 + 0.1 \times \sqrt{12} = 2.3464\)A1 Total: 3 marks. Condone > 4dp if correct
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y(3.2) = y(3) + 2(0.1)[f(3.1, y(3.1))]\)M1
\(= 2 + 2(0.1)[\sqrt{3.1^2 + 2.3464 + 1}]\)A1F ft on candidate's answer to (a)
\(= 2 + 0.2 \times 3.599499 = 2.720\)A1 Total: 3 marks. CAO Must be 2.720
# Question 1:

## Part (a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $y(3.1) = y(3) + 0.1\sqrt{3^2 + 2 + 1}$ | M1A1 | |
| $= 2 + 0.1 \times \sqrt{12} = 2.3464$ | A1 | Total: 3 marks. Condone > 4dp if correct |

## Part (b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $y(3.2) = y(3) + 2(0.1)[f(3.1, y(3.1))]$ | M1 | |
| $= 2 + 2(0.1)[\sqrt{3.1^2 + 2.3464 + 1}]$ | A1F | ft on candidate's answer to (a) |
| $= 2 + 0.2 \times 3.599499 = 2.720$ | A1 | Total: 3 marks. CAO Must be 2.720 |

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1 The function $y ( x )$ satisfies the differential equation

$$\frac { \mathrm { d } y } { \mathrm {~d} x } = \mathrm { f } ( x , y )$$

where

$$\mathrm { f } ( x , y ) = \sqrt { x ^ { 2 } + y + 1 }$$

and

$$y ( 3 ) = 2$$
\begin{enumerate}[label=(\alph*)]
\item Use the Euler formula

$$y _ { r + 1 } = y _ { r } + h \mathrm { f } \left( x _ { r } , y _ { r } \right)$$

with $h = 0.1$, to obtain an approximation to $y ( 3.1 )$, giving your answer to four decimal places.
\item Use the formula

$$y _ { r + 1 } = y _ { r - 1 } + 2 h \mathrm { f } \left( x _ { r } , y _ { r } \right)$$

with your answer to part (a), to obtain an approximation to $y ( 3.2 )$, giving your answer to three decimal places.
\end{enumerate}

\hfill \mbox{\textit{AQA FP3 2009 Q1 [6]}}