AQA FP3 2008 June — Question 2 7 marks

Exam BoardAQA
ModuleFP3 (Further Pure Mathematics 3)
Year2008
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeStandard linear first order - constant coefficients
DifficultyStandard +0.8 This is a Further Maths FP3 question requiring the method of undetermined coefficients for a non-homogeneous first-order linear ODE. Part (a) demands substituting a trial solution into the DE and equating coefficients across multiple terms (polynomial and trigonometric), which is algebraically involved. Part (b) requires finding the complementary function and combining solutions. While systematic, this exceeds standard A-level in both technique sophistication and algebraic manipulation required.
Spec4.10c Integrating factor: first order equations

2
  1. Find the values of the constants \(a , b , c\) and \(d\) for which \(a + b x + c \sin x + d \cos x\) is a particular integral of the differential equation $$\frac { \mathrm { d } y } { \mathrm {~d} x } - 3 y = 10 \sin x - 3 x$$ (4 marks)
  2. Hence find the general solution of this differential equation.

Question 2(a):
AnswerMarks Guidance
Working/AnswerMark Guidance
PI: \(y_{PI} = a + bx + c\sin x + d\cos x\), \(y'_{PI} = b + c\cos x - d\sin x\)
\(b + c\cos x - d\sin x - 3a - 3bx - 3c\sin x - 3d\cos x = 10\sin x - 3x\)M1 Substituting into DE
\(b-3a=0;\ -3b=-3;\ c-3d=0;\ -d-3c=10\)M1 Equating coefficients (at least 2 equations)
\(a = \frac{1}{3};\ b=1;\ c=-3;\ d=-1\)A2,1 A1 for any two correct
\(y_{PI} = \frac{1}{3} + x - 3\sin x - \cos x\)
Total part4
Question 2(b):
AnswerMarks Guidance
Working/AnswerMark Guidance
Aux. eqn. \(m - 3 = 0\)M1 Altn. \(\int y^{-1}\,dy = \int 3\,dx\) OE (M1)
\(y_{CF} = Ae^{3x}\)A1 \(Ae^{3x}\) OE
\(y_{GS} = Ae^{3x} + \frac{1}{3} + x - 3\sin x - \cos x\)B1F 3
Total7
## Question 2(a):

| Working/Answer | Mark | Guidance |
|---|---|---|
| PI: $y_{PI} = a + bx + c\sin x + d\cos x$, $y'_{PI} = b + c\cos x - d\sin x$ | | |
| $b + c\cos x - d\sin x - 3a - 3bx - 3c\sin x - 3d\cos x = 10\sin x - 3x$ | M1 | Substituting into DE |
| $b-3a=0;\ -3b=-3;\ c-3d=0;\ -d-3c=10$ | M1 | Equating coefficients (at least 2 equations) |
| $a = \frac{1}{3};\ b=1;\ c=-3;\ d=-1$ | A2,1 | A1 for any two correct |
| $y_{PI} = \frac{1}{3} + x - 3\sin x - \cos x$ | | |
| **Total part** | **4** | |

## Question 2(b):

| Working/Answer | Mark | Guidance |
|---|---|---|
| Aux. eqn. $m - 3 = 0$ | M1 | Altn. $\int y^{-1}\,dy = \int 3\,dx$ OE (M1) |
| $y_{CF} = Ae^{3x}$ | A1 | $Ae^{3x}$ OE |
| $y_{GS} = Ae^{3x} + \frac{1}{3} + x - 3\sin x - \cos x$ | B1F | 3 | (c's CF + c's PI) with 1 arbitrary constant |
| **Total** | **7** | |

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2
\begin{enumerate}[label=(\alph*)]
\item Find the values of the constants $a , b , c$ and $d$ for which $a + b x + c \sin x + d \cos x$ is a particular integral of the differential equation

$$\frac { \mathrm { d } y } { \mathrm {~d} x } - 3 y = 10 \sin x - 3 x$$

(4 marks)
\item Hence find the general solution of this differential equation.
\end{enumerate}

\hfill \mbox{\textit{AQA FP3 2008 Q2 [7]}}