OCR M2 2006 June — Question 1 4 marks

Exam BoardOCR
ModuleM2 (Mechanics 2)
Year2006
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeLifting objects vertically
DifficultyEasy -1.8 This is a straightforward one-step calculation requiring only the basic power formula P = mgh/t with all values directly given. It requires simple recall and substitution with no problem-solving, making it significantly easier than average A-level questions.
Spec6.02l Power and velocity: P = Fv
1 A child of mass 35 kg runs up a flight of stairs in 10 seconds. The vertical distance climbed is 4 m . Assuming that the child's speed is constant, calculate the power output.
Question 1:
AnswerMarks Guidance
WorkingMark Guidance
\(mgh = 35 \times 9.8 \times 4\)M1
\(\frac{mgh}{t} = \frac{1372}{10}\)A1, M1 watch out for extras
\(137\) WA1 4 marks total; or \(0.137\) kW 
# Question 1:

| Working | Mark | Guidance |
|---------|------|----------|
| $mgh = 35 \times 9.8 \times 4$ | M1 | |
| $\frac{mgh}{t} = \frac{1372}{10}$ | A1, M1 | watch out for extras |
| $137$ W | A1 | 4 marks total; or $0.137$ kW |

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1 A child of mass 35 kg runs up a flight of stairs in 10 seconds. The vertical distance climbed is 4 m . Assuming that the child's speed is constant, calculate the power output.

\hfill \mbox{\textit{OCR M2 2006 Q1 [4]}}
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