CAIE FP2 2019 June — Question 7 8 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2019
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCumulative distribution functions
TypePDF to CDF derivation
DifficultyStandard +0.3 This is a straightforward PDF to CDF question requiring integration of a simple polynomial function, followed by finding quartiles by solving F(x) = 0.25 and 0.75. While it involves multiple steps and some algebraic manipulation, the techniques are standard for Further Maths statistics with no conceptual challenges or novel problem-solving required.
Spec5.03e Find cdf: by integration5.03f Relate pdf-cdf: medians and percentiles

7 The continuous random variable \(X\) has probability density function f given by $$f ( x ) = \begin{cases} \frac { 3 } { 4 x ^ { 2 } } + \frac { 1 } { 4 } & 1 \leqslant x \leqslant 3 \\ 0 & \text { otherwise } \end{cases}$$
  1. Find the distribution function of \(X\).
  2. Find the exact value of the interquartile range of \(X\).

Question 7(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(F(x) = \int f(x)\,dx = -\frac{3}{4x} + \frac{x}{4}\ [+c]\)M1 Find or state distribution function \(F(x)\) for \(1 \leq x \leq 3\)
\(= -\frac{3}{4x} + \frac{x}{4} + \frac{1}{2}\) or \(\frac{1}{4}(-\frac{3}{x} + x + 2)\)A1 Using \(F(1)=0\) or \(F(3)=1\) to find \(c\) if necessary
\(F(x) = 0\ (x < \text{or} \leq 1)\), \(F(x) = 1\ (x > \text{or} \geq 3)\)A1 State \(F(x)\) for other values of \(x\)
3
Question 7(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\int_1^Q f(x)\,dx = -\frac{3}{4Q} + \frac{Q}{4} + \frac{1}{2} = \frac{1}{4}\) [or \(\frac{3}{4}\)] (AEF)M1 Formulate equation for either quartile value \(Q\)
\(Q^2 + [\text{or} -]\ Q - 3 = 0\)A1
\(Q_1 = \frac{1}{2}(-1+\sqrt{13})\), \(Q_3 = \frac{1}{2}(1+\sqrt{13})\)A1 A1 Find lower quartile \(Q_1\) and upper quartile \(Q_3\)
\(Q_3 - Q_1 = 1\)A1 Find interquartile range
5
## Question 7(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $F(x) = \int f(x)\,dx = -\frac{3}{4x} + \frac{x}{4}\ [+c]$ | M1 | Find or state distribution function $F(x)$ for $1 \leq x \leq 3$ |
| $= -\frac{3}{4x} + \frac{x}{4} + \frac{1}{2}$ or $\frac{1}{4}(-\frac{3}{x} + x + 2)$ | A1 | Using $F(1)=0$ or $F(3)=1$ to find $c$ if necessary |
| $F(x) = 0\ (x < \text{or} \leq 1)$, $F(x) = 1\ (x > \text{or} \geq 3)$ | A1 | State $F(x)$ for other values of $x$ |
| | **3** | |

## Question 7(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\int_1^Q f(x)\,dx = -\frac{3}{4Q} + \frac{Q}{4} + \frac{1}{2} = \frac{1}{4}$ [or $\frac{3}{4}$] (AEF) | M1 | Formulate equation for either quartile value $Q$ |
| $Q^2 + [\text{or} -]\ Q - 3 = 0$ | A1 | |
| $Q_1 = \frac{1}{2}(-1+\sqrt{13})$, $Q_3 = \frac{1}{2}(1+\sqrt{13})$ | A1 A1 | Find lower quartile $Q_1$ and upper quartile $Q_3$ |
| $Q_3 - Q_1 = 1$ | A1 | Find interquartile range |
| | **5** | |
7 The continuous random variable $X$ has probability density function f given by

$$f ( x ) = \begin{cases} \frac { 3 } { 4 x ^ { 2 } } + \frac { 1 } { 4 } & 1 \leqslant x \leqslant 3 \\ 0 & \text { otherwise } \end{cases}$$

(i) Find the distribution function of $X$.\\

(ii) Find the exact value of the interquartile range of $X$.\\

\hfill \mbox{\textit{CAIE FP2 2019 Q7 [8]}}