CAIE FP2 2015 June — Question 4 10 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2015
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypePrism or block on inclined plane
DifficultyChallenging +1.8 This is a challenging statics problem requiring analysis of two connected bodies (cube and rod) with multiple force components, friction at limiting equilibrium, and careful geometric reasoning to find distances. It demands systematic application of equilibrium conditions, resolution of forces in two directions, and taking moments about strategic points. The geometry with the 30° angle and the need to prove a specific inequality for μ adds complexity beyond standard mechanics questions, though the techniques are all A-level standard.
Spec3.03m Equilibrium: sum of resolved forces = 03.03n Equilibrium in 2D: particle under forces3.03r Friction: concept and vector form3.03u Static equilibrium: on rough surfaces3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force

4 \includegraphics[max width=\textwidth, alt={}, center]{833c338f-53c1-436e-a772-0cdaf17fa72d-3_559_1303_255_422} The diagram shows a central cross-section CDEF of a uniform solid cube of weight \(W\) and with edges of length \(2 a\). The cube rests on a rough horizontal plane. A thin uniform \(\operatorname { rod } A B\), of weight \(W\) and length \(6 a\), is hinged to the plane at \(A\). The rod rests in smooth contact with the cube at \(C\), with angle \(C A D\) equal to \(30 ^ { \circ }\). The rod is in the same vertical plane as \(C D E F\). The coefficient of friction between the plane and the cube is \(\mu\). Given that the system is in equilibrium, show that \(\mu \geqslant \frac { 3 } { 25 } \sqrt { } 3\). [6] Find the magnitude of the force acting on the \(\operatorname { rod }\) at \(A\).

Question 4:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(R_C \times 2a/\sin 30° = W \times 3a\cos 30°\) Find reaction at \(C\) using moments about \(A\)
\(R_C = 3\sqrt{3}W/8\)M1 A1
\(F = R_C\sin 30°\) [= \(3\sqrt{3}W/16\)]B1 Find friction \(F\) on cube
\(R = W + R_C\cos 30°\) [= \(25W/16\)]B1 Find reaction \(R\) on cube
\(3\sqrt{3}/16 \leq 25\mu/16\), \(\mu \geq 3\sqrt{3}/25\)M1 A1 Use \(F \leq \mu R\); AG (M0 if \(F = \mu R\))
\(X = F\) [= \(3\sqrt{3}W/16\)]B1 Find horizontal force \(X\) at \(A\)
\(Y = 2W - R\) or \(W - R_C\cos 30°\) [= \(7W/16\)]B1 Find vertical force \(Y\) at \(A\)
\(\sqrt{(X^2 + Y^2)} = (\sqrt{19}/8)\ W\) or \(0.545W\)M1 A1 Find magnitude of force at \(A\)
Total: 10
## Question 4:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $R_C \times 2a/\sin 30° = W \times 3a\cos 30°$ | | Find reaction at $C$ using moments about $A$ |
| $R_C = 3\sqrt{3}W/8$ | M1 A1 | |
| $F = R_C\sin 30°$ [= $3\sqrt{3}W/16$] | B1 | Find friction $F$ on cube |
| $R = W + R_C\cos 30°$ [= $25W/16$] | B1 | Find reaction $R$ on cube |
| $3\sqrt{3}/16 \leq 25\mu/16$, $\mu \geq 3\sqrt{3}/25$ | M1 A1 | Use $F \leq \mu R$; **AG** (M0 if $F = \mu R$) |
| $X = F$ [= $3\sqrt{3}W/16$] | B1 | Find horizontal force $X$ at $A$ |
| $Y = 2W - R$ or $W - R_C\cos 30°$ [= $7W/16$] | B1 | Find vertical force $Y$ at $A$ |
| $\sqrt{(X^2 + Y^2)} = (\sqrt{19}/8)\ W$ or $0.545W$ | M1 A1 | Find magnitude of force at $A$ |

**Total: 10**

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\includegraphics[max width=\textwidth, alt={}, center]{833c338f-53c1-436e-a772-0cdaf17fa72d-3_559_1303_255_422}

The diagram shows a central cross-section CDEF of a uniform solid cube of weight $W$ and with edges of length $2 a$. The cube rests on a rough horizontal plane. A thin uniform $\operatorname { rod } A B$, of weight $W$ and length $6 a$, is hinged to the plane at $A$. The rod rests in smooth contact with the cube at $C$, with angle $C A D$ equal to $30 ^ { \circ }$. The rod is in the same vertical plane as $C D E F$. The coefficient of friction between the plane and the cube is $\mu$. Given that the system is in equilibrium, show that $\mu \geqslant \frac { 3 } { 25 } \sqrt { } 3$. [6]

Find the magnitude of the force acting on the $\operatorname { rod }$ at $A$.

\hfill \mbox{\textit{CAIE FP2 2015 Q4 [10]}}