CAIE FP2 2014 June — Question 7 8 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2014
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Distribution
TypeFind threshold for given probability
DifficultyStandard +0.3 This question involves standard exponential distribution calculations: writing the pdf from the mean, computing P(T > 2000) using the exponential survival function, and finding a threshold by solving (e^(-t/1000))^10 ≥ 0.9. While it requires understanding of independence and taking logarithms, these are routine techniques for Further Maths students with no novel problem-solving required.
Spec1.06a Exponential function: a^x and e^x graphs and properties5.03a Continuous random variables: pdf and cdf5.03b Solve problems: using pdf

7 The random variable \(T\) is the lifetime, in hours, of a randomly chosen decorative light bulb of a particular type. It is given that \(T\) has a negative exponential distribution with mean 1000 hours.
  1. Write down the probability density function of \(T\).
  2. Find the probability that a randomly chosen bulb of this type has a lifetime of more than 2000 hours. A display uses 10 randomly chosen bulbs of this type, and they are all switched on simultaneously. Find the greatest value of \(t\) such that the probability that they are all alight at time \(t\) hours is at least 0.9 .

Question 7:
Part (i):
AnswerMarks Guidance
\(f(t) = 0.001\exp(-0.001t)\ \ (t \geq 0)\)B1 State probability density function of \(T\)
\([= 0 \quad \text{(otherwise or } t < 0)]\)
Part (ii):
AnswerMarks Guidance
\(P(t > 2000) = 1 - F(2000)\)M1 Find \(P(T > 2000)\)
\(= 1 - (1 - e^{-2}) = e^{-2}\) or \(0.135\)M1 A1 S.R. \(1 - e^{-2} = 0.865\) earns B1 only (max 1/3)
\((\exp(-0.001t))^{10} \geq [or >]\ 0.9\)M1 A1 State inequality for \(t\) (lose A1 if \(=\) or \(\leq\))
\(t_{\max} = (\ln 0.9)/(-0.01) = 10.5\)M1 A1 Solve for \(t_{\max}\); omitting power 10 earns 0/4; using \(1-(\exp(-0.001t))^{10}\) can earn M1 A0 M1 A0 only
# Question 7:

**Part (i):**
| $f(t) = 0.001\exp(-0.001t)\ \ (t \geq 0)$ | B1 | State probability density function of $T$ |
| $[= 0 \quad \text{(otherwise or } t < 0)]$ | | |

**Part (ii):**
| $P(t > 2000) = 1 - F(2000)$ | M1 | Find $P(T > 2000)$ |
| $= 1 - (1 - e^{-2}) = e^{-2}$ or $0.135$ | M1 A1 | S.R. $1 - e^{-2} = 0.865$ earns B1 only (max 1/3) |
| $(\exp(-0.001t))^{10} \geq [or >]\ 0.9$ | M1 A1 | State inequality for $t$ (lose A1 if $=$ or $\leq$) |
| $t_{\max} = (\ln 0.9)/(-0.01) = 10.5$ | M1 A1 | Solve for $t_{\max}$; omitting power 10 earns 0/4; using $1-(\exp(-0.001t))^{10}$ can earn M1 A0 M1 A0 only |

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7 The random variable $T$ is the lifetime, in hours, of a randomly chosen decorative light bulb of a particular type. It is given that $T$ has a negative exponential distribution with mean 1000 hours.\\
(i) Write down the probability density function of $T$.\\
(ii) Find the probability that a randomly chosen bulb of this type has a lifetime of more than 2000 hours.

A display uses 10 randomly chosen bulbs of this type, and they are all switched on simultaneously. Find the greatest value of $t$ such that the probability that they are all alight at time $t$ hours is at least 0.9 .

\hfill \mbox{\textit{CAIE FP2 2014 Q7 [8]}}