CAIE FP2 2009 June — Question 1 5 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2009
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypePosition vector circular motion
DifficultyChallenging +1.2 This is a Further Maths circular motion question requiring students to express position in vector form, differentiate to find velocity and acceleration, then compute and compare magnitudes. While it involves multiple calculus steps and vector manipulation, the approach is methodical: use r = l(cos θ, sin θ), apply chain rule with the given dθ/dt = sin θ, and show |v| = |a| through algebraic simplification. The conceptual demand is moderate for FP2 students familiar with parametric differentiation.
Spec6.02m Variable force power: using scalar product6.05e Radial/tangential acceleration

1 A line \(O P\) of fixed length \(l\) rotates in a plane about the fixed point \(O\). At time \(t = 0\), the line is at the position \(O A\). At time \(t\), angle \(A O P = \theta\) radians and \(\frac { \mathrm { d } \theta } { \mathrm { d } t } = \sin \theta\). Show that, for all \(t\), the magnitude of the acceleration of \(P\) is equal to the magnitude of its velocity.

Question 1:
AnswerMarks Guidance
Working/AnswerMark Guidance
\(l\cos\theta \, d\theta/dt = l\cos\theta\sin\theta\)M1 A1 Find tangential acceleration \(l\,d^2\theta/dt^2\)
\(l\sin^2\theta\)M1 A1 Find radial acceleration \(l(d\theta/dt)^2\)
\(l\sqrt{\cos^2\theta + \sin^2\theta}\sin\theta = l\sin\theta\)B1 Combine to give \(l\,d\theta/dt\) (ignore magnitudes). A.G. Total: 5
## Question 1:

| Working/Answer | Mark | Guidance |
|---|---|---|
| $l\cos\theta \, d\theta/dt = l\cos\theta\sin\theta$ | M1 A1 | Find tangential acceleration $l\,d^2\theta/dt^2$ |
| $l\sin^2\theta$ | M1 A1 | Find radial acceleration $l(d\theta/dt)^2$ |
| $l\sqrt{\cos^2\theta + \sin^2\theta}\sin\theta = l\sin\theta$ | B1 | Combine to give $l\,d\theta/dt$ (ignore magnitudes). **A.G.** Total: 5 |

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1 A line $O P$ of fixed length $l$ rotates in a plane about the fixed point $O$. At time $t = 0$, the line is at the position $O A$. At time $t$, angle $A O P = \theta$ radians and $\frac { \mathrm { d } \theta } { \mathrm { d } t } = \sin \theta$. Show that, for all $t$, the magnitude of the acceleration of $P$ is equal to the magnitude of its velocity.

\hfill \mbox{\textit{CAIE FP2 2009 Q1 [5]}}