CAIE P3 2019 March — Question 9 10 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2019
SessionMarch
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine of intersection of planes
DifficultyStandard +0.3 This is a standard two-part vectors question requiring routine techniques: finding the angle between planes using normal vectors and the dot product formula, then finding the line of intersection by solving simultaneous equations and using the cross product for direction. Both are textbook procedures with no novel insight required, making it slightly easier than average.
Spec4.04a Line equations: 2D and 3D, cartesian and vector forms4.04d Angles: between planes and between line and plane

9 Two planes have equations \(2 x + 3 y - z = 1\) and \(x - 2 y + z = 3\).
  1. Find the acute angle between the planes.
  2. Find a vector equation for the line of intersection of the planes.

Question 9(i):
AnswerMarks Guidance
AnswerMark Guidance
State or imply a correct normal vector to either plane, e.g. \(2\mathbf{i} + 3\mathbf{j} - \mathbf{k}\), or \(\mathbf{i} - 2\mathbf{j} + \mathbf{k}\)B1
Carry out correct process for evaluating the scalar product of two normal vectorsM1
Using the correct process for the moduli, divide the scalar product of the two normal vectors by the product of their moduli and evaluate the inverse cosine of the resultM1
Obtain answer \(56.9°\) or \(0.994\) radiansA1
Total4
Question 9(ii):
AnswerMarks Guidance
AnswerMark Guidance
*EITHER:* Carry out a complete strategy for finding a point on line \(l\)M1
Obtain such a point, e.g. \((1, 1, 4)\)A1
*EITHER:* State a correct equation for a direction vector \(a\mathbf{i} + b\mathbf{j} + c\mathbf{k}\) for \(l\), e.g. \(2a + 3b - c = 0\)B1
State a second equation, e.g. \(a - 2b + c = 0\), and solve for one ratio, e.g. \(a:b\)M1
Obtain \(a:b:c = 1:-3:-7\), or equivalentA1
State a correct answer, e.g. \(\mathbf{r} = \mathbf{i} + \mathbf{j} + 4\mathbf{k} + \lambda(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})\)A1
*OR1:* Attempt to calculate the vector product of the two normal vectorsM1
Obtain two correct componentsA1
Obtain \(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k}\), or equivalentA1
State a correct answer, e.g. \(\mathbf{r} = \mathbf{i} + \mathbf{j} + 4\mathbf{k} + \lambda(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})\), or equivalentA1
*OR2:* Obtain a second point on \(l\), e.g. \((0, 4, 11)\)B1
Subtract position vectors and obtain a direction vector for \(l\)M1
Obtain \(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k}\), or equivalentA1
State a correct answer, e.g. \(\mathbf{r} = 4\mathbf{j} + 11\mathbf{k} + \mu(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})\), or equivalentA1
*OR3:* Express one variable in terms of a secondM1
Obtain a correct simplified expression, e.g. \(y = 4 - 3x\)A1
Express the third variable in terms of the secondM1
Obtain a correct simplified expression, e.g. \(z = 11 - 7x\)A1
Form a vector equation for the lineM1
State a correct answer, e.g. \(\mathbf{r} = 4\mathbf{j} + 11\mathbf{k} + \lambda(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})\), or equivalentA1
*OR4:* Express one variable in terms of a secondM1
Obtain a correct simplified expression, e.g. \(x = \frac{4}{3} - \frac{y}{3}\)A1
Express the same variable in terms of the thirdM1
Obtain a correct simplified expression, e.g. \(x = \frac{11}{7} - \frac{z}{7}\)A1
Form a vector equation for the lineM1
Obtain a correct answer, e.g. \(\mathbf{r} = 4\mathbf{j} + 11\mathbf{k} + \mu(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})\), or equivalentA1
Total6
## Question 9(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| State or imply a correct normal vector to either plane, e.g. $2\mathbf{i} + 3\mathbf{j} - \mathbf{k}$, or $\mathbf{i} - 2\mathbf{j} + \mathbf{k}$ | B1 | |
| Carry out correct process for evaluating the scalar product of two normal vectors | M1 | |
| Using the correct process for the moduli, divide the scalar product of the two normal vectors by the product of their moduli and evaluate the inverse cosine of the result | M1 | |
| Obtain answer $56.9°$ or $0.994$ radians | A1 | |
| **Total** | **4** | |

## Question 9(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| *EITHER:* Carry out a complete strategy for finding a point on line $l$ | M1 | |
| Obtain such a point, e.g. $(1, 1, 4)$ | A1 | |
| *EITHER:* State a correct equation for a direction vector $a\mathbf{i} + b\mathbf{j} + c\mathbf{k}$ for $l$, e.g. $2a + 3b - c = 0$ | B1 | |
| State a second equation, e.g. $a - 2b + c = 0$, and solve for one ratio, e.g. $a:b$ | M1 | |
| Obtain $a:b:c = 1:-3:-7$, or equivalent | A1 | |
| State a correct answer, e.g. $\mathbf{r} = \mathbf{i} + \mathbf{j} + 4\mathbf{k} + \lambda(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})$ | A1 | |
| *OR1:* Attempt to calculate the vector product of the two normal vectors | M1 | |
| Obtain two correct components | A1 | |
| Obtain $\mathbf{i} - 3\mathbf{j} - 7\mathbf{k}$, or equivalent | A1 | |
| State a correct answer, e.g. $\mathbf{r} = \mathbf{i} + \mathbf{j} + 4\mathbf{k} + \lambda(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})$, or equivalent | A1 | |
| *OR2:* Obtain a second point on $l$, e.g. $(0, 4, 11)$ | B1 | |
| Subtract position vectors and obtain a direction vector for $l$ | M1 | |
| Obtain $\mathbf{i} - 3\mathbf{j} - 7\mathbf{k}$, or equivalent | A1 | |
| State a correct answer, e.g. $\mathbf{r} = 4\mathbf{j} + 11\mathbf{k} + \mu(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})$, or equivalent | A1 | |
| *OR3:* Express one variable in terms of a second | M1 | |
| Obtain a correct simplified expression, e.g. $y = 4 - 3x$ | A1 | |
| Express the third variable in terms of the second | M1 | |
| Obtain a correct simplified expression, e.g. $z = 11 - 7x$ | A1 | |
| Form a vector equation for the line | M1 | |
| State a correct answer, e.g. $\mathbf{r} = 4\mathbf{j} + 11\mathbf{k} + \lambda(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})$, or equivalent | A1 | |
| *OR4:* Express one variable in terms of a second | M1 | |
| Obtain a correct simplified expression, e.g. $x = \frac{4}{3} - \frac{y}{3}$ | A1 | |
| Express the same variable in terms of the third | M1 | |
| Obtain a correct simplified expression, e.g. $x = \frac{11}{7} - \frac{z}{7}$ | A1 | |
| Form a vector equation for the line | M1 | |
| Obtain a correct answer, e.g. $\mathbf{r} = 4\mathbf{j} + 11\mathbf{k} + \mu(\mathbf{i} - 3\mathbf{j} - 7\mathbf{k})$, or equivalent | A1 | |
| **Total** | **6** | |
9 Two planes have equations $2 x + 3 y - z = 1$ and $x - 2 y + z = 3$.\\
(i) Find the acute angle between the planes.\\

(ii) Find a vector equation for the line of intersection of the planes.\\

\hfill \mbox{\textit{CAIE P3 2019 Q9 [10]}}