CAIE FP1 2019 June — Question 6 9 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2019
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeStationary Points of Rational Functions
DifficultyStandard +0.8 This Further Pure 1 question requires finding asymptotes (vertical and oblique via polynomial division), differentiating a rational function using the quotient rule, solving a quadratic equation for stationary points, and producing an accurate sketch integrating all features. While systematic, it demands multiple techniques and careful algebraic manipulation across several parts, placing it moderately above average difficulty.
Spec1.02n Sketch curves: simple equations including polynomials1.02o Sketch reciprocal curves: y=a/x and y=a/x^21.07n Stationary points: find maxima, minima using derivatives

6 The curve \(C\) has equation $$y = \frac { x ^ { 2 } } { k x - 1 }$$ where \(k\) is a positive constant.
  1. Obtain the equations of the asymptotes of \(C\).
  2. Find the coordinates of the stationary points of \(C\).
  3. Sketch \(C\).

Question 6(i):
AnswerMarks Guidance
\(x = \frac{1}{k}\)B1 States vertical asymptote
\(y = \frac{(kx-1)(k^{-1}x + k^{-2}) + k^{-2}}{kx-1}\)M1 Finds oblique asymptote
Oblique asymptote is \(y = k^{-1}x + k^{-2}\)A1
Question 6(ii):
AnswerMarks Guidance
\(y' = \frac{2x(kx-1) - kx^2}{(kx-1)^2} = 0 \Rightarrow kx^2 - 2x = 0\)M1 Differentiates and equates to 0
\(x = 0,\ 2k^{-1}\)A1 Finds \(x\)-coordinates
\((0,0),\ \left(2k^{-1}, 4k^{-2}\right)\)A1 Finds \(y\)-coordinates
Question 6(iii):
AnswerMarks Guidance
Graph with correct axes and asymptotesB1 Axes and asymptotes correct
Upper branch correctB1 Upper branch correct
Lower branch correctB1 Lower branch correct; deduct at most 1 mark for poor forms at infinity
## Question 6(i):

| $x = \frac{1}{k}$ | B1 | States vertical asymptote |
| $y = \frac{(kx-1)(k^{-1}x + k^{-2}) + k^{-2}}{kx-1}$ | M1 | Finds oblique asymptote |
| Oblique asymptote is $y = k^{-1}x + k^{-2}$ | A1 | |

## Question 6(ii):

| $y' = \frac{2x(kx-1) - kx^2}{(kx-1)^2} = 0 \Rightarrow kx^2 - 2x = 0$ | M1 | Differentiates and equates to 0 |
| $x = 0,\ 2k^{-1}$ | A1 | Finds $x$-coordinates |
| $(0,0),\ \left(2k^{-1}, 4k^{-2}\right)$ | A1 | Finds $y$-coordinates |

## Question 6(iii):

| Graph with correct axes and asymptotes | B1 | Axes and asymptotes correct |
| Upper branch correct | B1 | Upper branch correct |
| Lower branch correct | B1 | Lower branch correct; deduct at most 1 mark for poor forms at infinity |
6 The curve $C$ has equation

$$y = \frac { x ^ { 2 } } { k x - 1 }$$

where $k$ is a positive constant.\\
(i) Obtain the equations of the asymptotes of $C$.\\

(ii) Find the coordinates of the stationary points of $C$.\\

(iii) Sketch $C$.

\hfill \mbox{\textit{CAIE FP1 2019 Q6 [9]}}