CAIE FP1 2017 June — Question 7 8 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2017
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeFinding polynomial from root properties
DifficultyChallenging +1.2 This is a standard Further Maths technique of converting symmetric function conditions into a polynomial via Vieta's formulas. Students must recognize that the three given equations translate to elementary symmetric polynomials (sum of roots = -1, sum of products of pairs can be derived from the second equation using the identity, and sum of reciprocals gives product of roots), then construct and solve the cubic. While it requires multiple steps and is beyond Core A-level, it's a textbook FP1 exercise with a well-established method.
Spec4.05a Roots and coefficients: symmetric functions

7 By finding a cubic equation whose roots are \(\alpha , \beta\) and \(\gamma\), solve the set of simultaneous equations $$\begin{aligned} \alpha + \beta + \gamma & = - 1 , \\ \alpha ^ { 2 } + \beta ^ { 2 } + \gamma ^ { 2 } & = 29 , \\ \frac { 1 } { \alpha } + \frac { 1 } { \beta } + \frac { 1 } { \gamma } & = - 1 . \end{aligned}$$

Question 7:
AnswerMarks Guidance
AnswerMarks Guidance
\(2\sum\alpha\beta = 1 - 29 \Rightarrow \sum\alpha\beta = -14\)M1A1
\(\frac{\sum\alpha\beta}{\alpha\beta\gamma} = \frac{-14}{\alpha\beta\gamma} = -1 \Rightarrow \alpha\beta\gamma = 14\)M1A1 FT
\(\Rightarrow x^3 + x^2 - 14x - 14 = 0\)A1
\(\Rightarrow (x+1)(x^2-14)\)M1A1 Attempt to factorise cubic
Solution is \(-1\), \(\pm\sqrt{14}\), any order. Accept \(\pm3.74\) (awrt). SR B1 for correct roots without workingA1
## Question 7:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $2\sum\alpha\beta = 1 - 29 \Rightarrow \sum\alpha\beta = -14$ | M1A1 | |
| $\frac{\sum\alpha\beta}{\alpha\beta\gamma} = \frac{-14}{\alpha\beta\gamma} = -1 \Rightarrow \alpha\beta\gamma = 14$ | M1A1 FT | |
| $\Rightarrow x^3 + x^2 - 14x - 14 = 0$ | A1 | |
| $\Rightarrow (x+1)(x^2-14)$ | M1A1 | Attempt to factorise cubic |
| Solution is $-1$, $\pm\sqrt{14}$, any order. Accept $\pm3.74$ (awrt). SR **B1** for correct roots without working | A1 | |
7 By finding a cubic equation whose roots are $\alpha , \beta$ and $\gamma$, solve the set of simultaneous equations

$$\begin{aligned}
\alpha + \beta + \gamma & = - 1 , \\
\alpha ^ { 2 } + \beta ^ { 2 } + \gamma ^ { 2 } & = 29 , \\
\frac { 1 } { \alpha } + \frac { 1 } { \beta } + \frac { 1 } { \gamma } & = - 1 .
\end{aligned}$$

\hfill \mbox{\textit{CAIE FP1 2017 Q7 [8]}}