CAIE FP1 2012 June — Question 9 11 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2012
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine of intersection of planes
DifficultyStandard +0.3 This is a standard three-part Further Maths question on planes requiring routine techniques: finding a normal vector via cross product for the Cartesian equation, using the dot product formula for angle between planes, and solving simultaneous equations for the line of intersection. While it involves multiple steps and Further Maths content, each part follows well-established procedures without requiring novel insight or particularly challenging problem-solving.
Spec1.10a Vectors in 2D: i,j notation and column vectors4.04b Plane equations: cartesian and vector forms4.04c Scalar product: calculate and use for angles4.04d Angles: between planes and between line and plane4.04f Line-plane intersection: find point

9 The plane \(\Pi _ { 1 }\) has parametric equation $$\mathbf { r } = 2 \mathbf { i } - 3 \mathbf { j } + \mathbf { k } + \lambda ( \mathbf { i } - 2 \mathbf { j } - \mathbf { k } ) + \mu ( \mathbf { i } + 2 \mathbf { j } - 2 \mathbf { k } )$$ Find a cartesian equation of \(\Pi _ { 1 }\). The plane \(\Pi _ { 2 }\) has cartesian equation \(3 x - 2 y - 3 z = 4\). Find the acute angle between \(\Pi _ { 1 }\) and \(\Pi _ { 2 }\). Find a vector equation of the line of intersection of \(\Pi _ { 1 }\) and \(\Pi _ { 2 }\).

Question 9:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 1 & -2 & -1 \\ 1 & 2 & -2 \end{vmatrix} = \begin{pmatrix} 6 \\ 1 \\ 4 \end{pmatrix}\)M1A1 Finds normal vector to plane
Plane equation \(6x + y + 4z =\) constant; substitute \((2,-3,1) \Rightarrow 12-3+4=13\)M1 Uses known point to find constant term
\(\Rightarrow \Pi_1: 6x + y + 4z = 13\)A1 4 marks total
\(\cos\theta = \frac{(6\mathbf{i}+\mathbf{j}+4\mathbf{k})\cdot(3\mathbf{i}-2\mathbf{j}-3\mathbf{k})}{\sqrt{6^2+1^2+4^2}\sqrt{3^2+2^2+3^2}} = \frac{4}{\sqrt{53}\sqrt{22}}\)M1A1 Angle between normals equals angle between planes
\(\Rightarrow \theta = 83.3°\) or \(1.45\) radA1 3 marks total
\(6x+y+4z=13\) and \(3x-2y-3z=4\); obtains e.g. \(y+2z=1\) and \(3x+z=6\)M1 Solve plane equations simultaneously
Or two of \((0,-11,6)\), \((11/6, 0, 1/2)\), \((2,1,0)\)A1A1
\(\begin{pmatrix}x\\y\\z\end{pmatrix} = \begin{pmatrix}2\\1\\0\end{pmatrix} + t\begin{pmatrix}-1\\-6\\3\end{pmatrix}\)A1 4 marks total
Alternatively: Direction of line from vector product (M1A1); finds a point on line (A1); states equation of line (A1)
## Question 9:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 1 & -2 & -1 \\ 1 & 2 & -2 \end{vmatrix} = \begin{pmatrix} 6 \\ 1 \\ 4 \end{pmatrix}$ | M1A1 | Finds normal vector to plane |
| Plane equation $6x + y + 4z =$ constant; substitute $(2,-3,1) \Rightarrow 12-3+4=13$ | M1 | Uses known point to find constant term |
| $\Rightarrow \Pi_1: 6x + y + 4z = 13$ | A1 | 4 marks total |
| $\cos\theta = \frac{(6\mathbf{i}+\mathbf{j}+4\mathbf{k})\cdot(3\mathbf{i}-2\mathbf{j}-3\mathbf{k})}{\sqrt{6^2+1^2+4^2}\sqrt{3^2+2^2+3^2}} = \frac{4}{\sqrt{53}\sqrt{22}}$ | M1A1 | Angle between normals equals angle between planes |
| $\Rightarrow \theta = 83.3°$ or $1.45$ rad | A1 | 3 marks total |
| $6x+y+4z=13$ and $3x-2y-3z=4$; obtains e.g. $y+2z=1$ and $3x+z=6$ | M1 | Solve plane equations simultaneously |
| Or two of $(0,-11,6)$, $(11/6, 0, 1/2)$, $(2,1,0)$ | A1A1 | |
| $\begin{pmatrix}x\\y\\z\end{pmatrix} = \begin{pmatrix}2\\1\\0\end{pmatrix} + t\begin{pmatrix}-1\\-6\\3\end{pmatrix}$ | A1 | 4 marks total |

**Alternatively:** Direction of line from vector product (M1A1); finds a point on line (A1); states equation of line (A1)

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9 The plane $\Pi _ { 1 }$ has parametric equation

$$\mathbf { r } = 2 \mathbf { i } - 3 \mathbf { j } + \mathbf { k } + \lambda ( \mathbf { i } - 2 \mathbf { j } - \mathbf { k } ) + \mu ( \mathbf { i } + 2 \mathbf { j } - 2 \mathbf { k } )$$

Find a cartesian equation of $\Pi _ { 1 }$.

The plane $\Pi _ { 2 }$ has cartesian equation $3 x - 2 y - 3 z = 4$. Find the acute angle between $\Pi _ { 1 }$ and $\Pi _ { 2 }$.

Find a vector equation of the line of intersection of $\Pi _ { 1 }$ and $\Pi _ { 2 }$.

\hfill \mbox{\textit{CAIE FP1 2012 Q9 [11]}}