OCR FP1 2012 January — Question 1 4 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2012
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Argand & Loci
TypeModulus-argument form conversion
DifficultyEasy -1.2 This is a straightforward application of the modulus formula |z| = √(a² + b²) to find a, followed by basic arctangent calculation for the argument. It requires only direct substitution and simple algebraic manipulation with no problem-solving insight needed.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02b Express complex numbers: cartesian and modulus-argument forms

1 The complex number \(a + 5 \mathrm { i }\), where \(a\) is positive, is denoted by \(z\). Given that \(| z | = 13\), find the value of \(a\) and hence find \(\arg z\).

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(a^2 + 5^2 = 13^2\), \(a = 12\)M1, A1 Use formula for modulus; Obtain correct answer
\(\tan^{-1}\frac{5}{a}\)M1 Use formula for argument
\(0.395\) or \(22.6°\) or \(0.126\pi\)A1FT Obtain correct answer; allow \(0.39\)
[4]
## Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $a^2 + 5^2 = 13^2$, $a = 12$ | M1, A1 | Use formula for modulus; Obtain correct answer |
| $\tan^{-1}\frac{5}{a}$ | M1 | Use formula for argument |
| $0.395$ or $22.6°$ or $0.126\pi$ | A1FT | Obtain correct answer; allow $0.39$ |
| **[4]** | | |

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1 The complex number $a + 5 \mathrm { i }$, where $a$ is positive, is denoted by $z$. Given that $| z | = 13$, find the value of $a$ and hence find $\arg z$.

\hfill \mbox{\textit{OCR FP1 2012 Q1 [4]}}