OCR FP1 2012 January — Question 8 8 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2012
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeInfinite series convergence and sum
DifficultyStandard +0.3 This is a standard telescoping series question with clear scaffolding. Part (i) is routine algebraic verification, part (ii) applies the telescoping technique to find a finite sum (a common FP1 exercise), and part (iii) uses the limit of the finite sum to find the infinite tail. While it requires understanding of partial fractions and series convergence, the question structure guides students through each step without requiring novel insight.
Spec4.06b Method of differences: telescoping series

8
  1. Show that \(\frac { r } { r + 1 } - \frac { r - 1 } { r } \equiv \frac { 1 } { r ( r + 1 ) }\).
  2. Hence find an expression, in terms of \(n\), for $$\frac { 1 } { 2 } + \frac { 1 } { 6 } + \frac { 1 } { 12 } + \ldots + \frac { 1 } { n ( n + 1 ) }$$
  3. Hence find \(\sum _ { r = n + 1 } ^ { \infty } \frac { 1 } { r ( r + 1 ) }\).

Question 8(i):
AnswerMarks Guidance
AnswerMarks Guidance
Combine with a common denominatorM1
Obtain given answer correctlyA1
[2]
Question 8(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\dfrac{n}{n+1}\)M1, A1, M1, A1 Express terms using (i); At least 1st two and last two correct; Show terms cancelling; Obtain correct answer in terms of \(n\)
[4]
Question 8(iii):
AnswerMarks Guidance
AnswerMarks Guidance
\(1 - \dfrac{n}{n+1}\)B1 \(\lim_{n\to\infty}\frac{n}{n+1}=1\)
B1FTThis value \(-\) (ii)
[2]
## Question 8(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Combine with a common denominator | M1 | |
| Obtain given answer correctly | A1 | |
| **[2]** | | |

---

## Question 8(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\dfrac{n}{n+1}$ | M1, A1, M1, A1 | Express terms using (i); At least 1st two and last two correct; Show terms cancelling; Obtain correct answer in terms of $n$ |
| **[4]** | | |

---

## Question 8(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $1 - \dfrac{n}{n+1}$ | B1 | $\lim_{n\to\infty}\frac{n}{n+1}=1$ |
| | B1FT | This value $-$ (ii) |
| **[2]** | | |

---
8 (i) Show that $\frac { r } { r + 1 } - \frac { r - 1 } { r } \equiv \frac { 1 } { r ( r + 1 ) }$.\\
(ii) Hence find an expression, in terms of $n$, for

$$\frac { 1 } { 2 } + \frac { 1 } { 6 } + \frac { 1 } { 12 } + \ldots + \frac { 1 } { n ( n + 1 ) }$$

(iii) Hence find $\sum _ { r = n + 1 } ^ { \infty } \frac { 1 } { r ( r + 1 ) }$.\\

\hfill \mbox{\textit{OCR FP1 2012 Q8 [8]}}