OCR MEI M1 2010 June — Question 1 3 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Year2010
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeVertical motion under gravity
DifficultyEasy -1.2 This is a straightforward one-step SUVAT problem requiring direct application of v² = u² + 2as with u=0, a=9.8 m/s², s=0.75m. It's simpler than average A-level questions as it requires only one equation with no problem-solving or multi-step reasoning, though students must remember to convert units.
Spec3.02d Constant acceleration: SUVAT formulae3.02g Two-dimensional variable acceleration
1 An egg falls from rest a distance of 75 cm to the floor.
Neglecting air resistance, at what speed does it hit the floor?
Question 1:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(v^2 = 0^2 + 2 \times 9.8 \times 0.75\)M1 Use of \(v^2 = u^2 + 2as\) with \(u = 0\) and \(a = \pm g\). Accept muddled units and sign errors.
A1Allow wrong or wrongly converted units, not sign errors
\(v = \pm 3.8340...\) so \(3.83 \text{ m s}^{-1}\) (3 s.f.)A1 cao. [SC2 for 38.3... seen WWW and SC3 for 3.83... seen WWW] 
# Question 1:

## Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $v^2 = 0^2 + 2 \times 9.8 \times 0.75$ | M1 | Use of $v^2 = u^2 + 2as$ with $u = 0$ and $a = \pm g$. Accept muddled units and sign errors. |
| | A1 | Allow wrong or wrongly converted units, not sign errors |
| $v = \pm 3.8340...$ so $3.83 \text{ m s}^{-1}$ (3 s.f.) | A1 | cao. [SC2 for 38.3... seen WWW and SC3 for 3.83... seen WWW] |

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1 An egg falls from rest a distance of 75 cm to the floor.\\
Neglecting air resistance, at what speed does it hit the floor?

\hfill \mbox{\textit{OCR MEI M1 2010 Q1 [3]}}
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