| Exam Board | OCR MEI |
|---|---|
| Module | C4 (Core Mathematics 4) |
| Year | 2015 |
| Session | June |
| Marks | 18 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Differential equations |
| Type | Logistic/bounded growth |
| Difficulty | Standard +0.3 This is a structured, multi-part differential equations question with clear scaffolding. Part (i) is routine partial fractions, part (ii) is guided separation of variables with the answer given, part (iii) involves straightforward substitution and logarithms, and part (iv) is algebraic rearrangement plus a simple limit. While it covers several techniques, each step is standard for C4 with no novel insight required, making it slightly easier than average. |
| Spec | 1.02y Partial fractions: decompose rational functions1.06i Exponential growth/decay: in modelling context1.08k Separable differential equations: dy/dx = f(x)g(y) |
| 5 | \includegraphics[max width=\textwidth, alt={}]{132ae754-bd4c-4819-80ef-4823ac2ead4f-08_1095_816_484_700} |
| 6 | |
**Question 7:** [3 marks]
Explanation using Table 2 to support claim about stopping at every floor
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7 A drug is administered by an intravenous drip. The concentration, $x$, of the drug in the blood is measured as a fraction of its maximum level. The drug concentration after $t$ hours is modelled by the differential equation
$$\frac { \mathrm { d } x } { \mathrm {~d} t } = k \left( 1 + x - 2 x ^ { 2 } \right) ,$$
where $0 \leqslant x < 1$, and $k$ is a positive constant. Initially, $x = 0$.\\
(i) Express $\frac { 1 } { ( 1 + 2 x ) ( 1 - x ) }$ in partial fractions.\\
(ii) Hence solve the differential equation to show that $\frac { 1 + 2 x } { 1 - x } = \mathrm { e } ^ { 3 k t }$.\\
(iii) After 1 hour the drug concentration reaches $75 \%$ of its maximum value and so $x = 0.75$.
Find the value of $k$, and the time taken for the drug concentration to reach $90 \%$ of its maximum value.\\
(iv) Rearrange the equation in part (ii) to show that $x = \frac { 1 - \mathrm { e } ^ { - 3 k t } } { 1 + 2 \mathrm { e } ^ { - 3 k t } }$.
Verify that in the long term the drug concentration approaches its maximum value.
\section*{END OF QUESTION PAPER}
\section*{Tuesday 16 J une 2015 - Afternoon}
\section*{A2 GCE MATHEMATICS (MEI)}
4754/01B Applications of Advanced Mathematics (C4) Paper B: Comprehension
\section*{QUESTION PAPER}
\section*{Candidates answer on the Question Paper.}
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\item MEI Examination Formulae and Tables (MF2)
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\item Scientific or graphical calculator
\item Rough paper
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Duration: Up to 1 hour\\
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2 In line 79 it says "For most journeys, more than half the journey time is composed of load time and transfer time". For what percentage of the journey time for the round trip made by car A in Table 4 is the car stationary?
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3 Using the expression on line 51, work out the answer to the question on lines 39 and 40 for the case where there are 10 upper floors and 7 people. Give your answer to 2 decimal places.
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4 In lines 89 and 90 it says "... on average there will be approximately 8 stops per trip. A round trip with 8 stops would take between 188 and 200 seconds". Explain how the figure of 188 seconds has been derived.
5 (i) Referring to Strategy 3 and lines 99 to 101, complete the table below for car C .\\
(ii) Calculate the time car C will take to transport all the people who work on floors 7 and 8 , and return to the ground floor.
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68 people make independent visits to any one of the upper floors of a building with 10 upper floors. What is the probability that at least one of the visitors goes to the top floor?
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7 On lines 94 and 95 it says "Table 4 gives the timings for round trips in which the cars are required to stop at every floor they serve; Table 2 suggests this is a common occurrence in this case". Explain how Table 2 is used to make this claim.\\
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END OF QUESTION PAPER
\hfill \mbox{\textit{OCR MEI C4 2015 Q7 [18]}}